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使用 Python,我想将匹配模式的文件sample1从 AWS S3 直接复制到 FTP 服务器,而无需下载到本地临时位置。我尝试了以下操作:

import s3fs
from ftplib import FTP_TLS

s3 = s3fs.S3FileSystem(anon=False)
pattern = 'sample1'
rest = [i for i in list if pattern in i]
rest

ftp = FTP_TLS("ftp.test.com")
ftp.login(user ='myUser', passwd = 'PassWrd')
ftp.cwd("box_dest")

for f in rest:
    print(f)
    with open(f, 'r') as fu:
        ftp.storbinary('STOR ' + f, fu)

我越来越:

[u'test-bucket/abc/test/sample1.csv']
test-bucket/abc/test/sample1.csv
Traceback (most recent call last):
  File "<stdin>", line 3, in <module>
IOError: [Errno 2] No such file or directory: u'test-bucket/abc/test/sample1.csv'

关于如何实现这一目标的任何建议?谢谢!

4

1 回答 1

0

要从 S3 读取文件,您需要使用S3FileSystem.open,而不是os.open.

在指定目标 FTP 路径时,您只需从原始 S3 路径中提取文件名。posixpath.basename应该做。

for f in rest:
    print(f)
    with s3.open(f, 'r') as fu:
        ftp.storbinary('STOR ' + posixpath.basename(f), fu)
于 2020-08-21T07:18:04.977 回答