c# - 如何在 c# 中使用 SpiceSharp 中的任何类？我无法在我的代码中使用二极管类，但我知道如何使用电阻器类和电压

Question

二极管线不工作，我不知道如何运行，请帮忙，我真的很想知道如何初始化二极管部分，一切正常，只有这部分当我添加它时它说找不到 ISimulation 模型

using System;
using SpiceSharp;
using SpiceSharp.Components;
using SpiceSharp.Simulations;
using System.Threading;


namespace SpiceSimulation
{
    class Program
    {
        static void Main(string[] args)
        { 
    var ckt = new Circuit(
         new VoltageSource("V0", "in1", "0", 0.0),//ground
         new VoltageSource("V1", "in", "in1", 12.0),//voltage source 12 volt
         new Resistor("R1", "out", "in", 1.0e3),//resistor 1k
         new Diode("M1", "out", "d", "ISimulation"),//here is my problem
         new Resistor("R2", "0", "d", 2.0e3)//resistor 2k
    
         );
    
    // Create a DC sweep and register to the event for exporting simulation data
    var dc = new DC("dc", "V0", 0.0, 0.0, 0.001);//ground voltage
        dc.ExportSimulationData += (sender, exportDataEventArgs) =>
        {
        Console.WriteLine(exportDataEventArgs.GetVoltage("out"));//get the voltage at this point
        };
    // Run the simulation
    dc.Run(ckt);//it will run the circuit

}
}
}

Answer 1

错误提示：“未找到 ISimulation 模型”表示您引用了不属于电路的模型“ISimulation”。您可以为您创建一个DiodeModel二极管并将其添加到电路中。例如：

var model = new DiodeModel("ISimulation");
model.SetParameter("is", 2.52e-9);
model.SetParameter("rs", 0.568);
model.SetParameter("n", 1.752);
model.SetParameter("cjo", 4e-12);
model.SetParameter("m", 0.4);
model.SetParameter("tt", 20e-9);

var ckt = new Circuit(
     new VoltageSource("V0", "in1", "0", 0.0),
     new VoltageSource("V1", "in", "in1", 12.0),
     new Resistor("R1", "out", "in", 1.0e3),
     model, // <-- Here goes model
     new Diode("M1", "out", "d", model.Name),// <-- The name is taken directly from model
     new Resistor("R2", "0", "d", 2.0e3)

     );

因此，如果我理解正确，DiodeModel 就是您要放置在电路上的二极管的确切类型。这允许计算电路。如果您有许多类似的元素（例如二极管电桥），可以重复使用模型