对此问题的后续问题 -如何使用 UrlfetchApp 修复无效的 url 错误?
这是从以下网址下载 excel 数据的网址:
https://corvo-reports.s3.amazonaws.com/TRESAH/2020-08-16/45d32ff8-bccd-4c16-8916-6c19c28f2f3c%402020-08-16%2017%3A30%3A00.0/Sponsored%20Products%20Search%20term%20report%20-%20Scotch%20Brite.xlsx?X-Amz-Algorithm=AWS4-HMAC-SHA256&X-Amz-Date=20200816T174421Z&X-Amz-SignedHeaders=host&X-Amz-Expires=604799&X-Amz-Credential=AKIAY2R3XYZC46Q4PK5E%2F20200816%2Fus-east-1%2Fs3%2Faws4_request&X-Amz-Signature=726ca9b98cd766966b756bc708b780377ff62e5bbfec8c09b97294bfb0cd63f7
这是一份按计划提交的报告,我需要获取这些数据并将其放入谷歌表格中。这是一个很大的报告,所以我需要清除工作表上的所有现有数据并用新数据替换它。我一直在为此苦苦挣扎,可以使用一些帮助。
这是我现在拥有的代码:
// Globals
const DataFolderId = 'XXXXX'
const label = 'YYYYY'
/*
* Download the excel file and put it in a google sheet
*
* @return : Hopefully, it adds the data to the google sheet
*/
function excelToSheets() {
// Get the link to the excel file
const url = getDownloadLink(label)
const excelFile = UrlFetchApp.fetch(url).getBlob()
const filename = 'Report: ' + Utilities.formatDate(new Date(), "IST", "yyyy-MM-dd")
// Download the file to google drive
const fileInfo = {
title: filename,
mimeType: "MICROSOFT_EXCEL",
"parents": [{'id': DataFolderId}],
}
// Currently, this adds a zip file to google drive, instead of an excel/google sheet file
const file = Drive.Files.insert(fileInfo, excelFile, {convert: true})
// Assign the id of the downloaded file to a variable
const id = file.id
// Put data in a spreadsheet - this does not work
spreadsheet(id)
}
/*
* Helper function to put data in the google sheet
*/
function spreadsheet (id) {
const source = SpreadsheetApp.openById(id)
const destination = SpreadsheetApp.getActiveSpreadsheet().getSheetByName('data')
destination.clearContents()
source.copyTo(destination)
}
/*
* Get the download link from the gmail label
*
* @return : The link from the most recent email
*/
function getDownloadLink (label) {
const lookupLabel = GmailApp.getUserLabelByName(label)
const thread = lookupLabel.getThreads()[0]
const message = thread.getMessages()[0]
const data = message.getPlainBody()
const regExp = new RegExp('[\n\r].*Download:\\s*([^\n\r]*)')
const link = regExp.exec(data)[1].trim()
return link
}
目前,该excelToSheets()函数从链接中获取 excel 文件,并在 google 驱动器中添加一个 zip 文件。我不确定我在这里做错了什么 - 我一直在尝试在线关注一堆关于该主题的教程。
您的帮助将不胜感激!