我使用 2 LiveData
s 从单独的表到我的应用程序的存储库中。我将这两个LiveData
s 作为源添加到CustomMediatorLiveData
扩展的类中MediatorLiveData
。在each 方法的onChanged
回调中,我将两个s 的值发送到一个将两者结合并返回一个设置为对象的单个方法中。我在我的存储库中创建了一个对象,并将这两个s 作为构造函数的参数传递。addSource
LiveData
LiveData
LiveData
value
CustomMediatorLiveData
CustomMediatorLiveData
LiveData
这会运行并且不会给出任何错误,但它会弄乱 LiveData 本身的数据。
示例:如果日期最初是 2020 年 8 月 15 日,那么它可能类似于 0001 年 8 月 14 日。
CustomMediatorLiveData:
public class CustomMediatorLiveData extends MediatorLiveData<List<Object>> {
private List<Note> notes = Collections.emptyList();
private List<RecurringTask> recurringTasks = Collections.emptyList();
public CustomMediatorLiveData(LiveData<List<Note>> liveNotes, LiveData<List<RecurringTask>> liveRecurringTasks) {
addSource(liveNotes, notes1 -> {
if (notes1 != null) {
this.notes = notes1;
}
setValue(combineData(notes,recurringTasks));
});
addSource(liveRecurringTasks, recurringTasks1 -> {
if (recurringTasks1 != null) {
this.recurringTasks = recurringTasks1;
}
setValue(combineData(notes,recurringTasks));
});
}
// This method adds the 2 lists into one and sorts them based on dates and priority.
private List<Object> combineData(List<Note> notes, List<RecurringTask> recurringTasks) {
List<Object> combinedList = new ArrayList<>();
if (notes != null && !notes.isEmpty())
combinedList.addAll(notes);
if(recurringTasks!=null && !recurringTasks.isEmpty())
combinedList.addAll(recurringTasks);
Collections.sort(combinedList, new Comparator<Object>() {
@Override
public int compare(Object o1, Object o2) {
Date d1, d2;
Note n1 = null, n2 = null;
RecurringTask r1 = null, r2 = null;
if (o1 instanceof Note && o2 instanceof Note) {
int hmm = Boolean.compare(((Note) o2).isPriority(), ((Note) o1).isPriority());
if (hmm != 0)
return hmm;
}
if (o1 instanceof Note) {
d1 = ((Note) o1).getEnd_date();
n1 = ((Note) o1);
} else {
d1 = ((RecurringTask) o1).getEnd_date();
r1 = ((RecurringTask) o1);
}
if (o2 instanceof Note) {
d2 = ((Note) o2).getEnd_date();
n2 = ((Note) o2);
} else {
d2 = ((RecurringTask) o2).getEnd_date();
r2 = ((RecurringTask) o2);
}
if (n1 != null) {
if (r2 != null) {
if (n1.isPriority()) {
return -1;
}
}
}
if (n2 != null) {
if (r1 != null) {
if (n2.isPriority()) {
return 1;
}
}
}
long l1 = d1.getTime() - d2.getTime();
if (l1 > 0) {
return 1;
} else if (l1 < 0) {
return -1;
} else {
return 0;
}
}
});
return combinedList;
}
}
注意存储库类:
public class NoteRepository {
private String DB_NAME = "db_task";
Context context;
private RecurringDao recurringDao;
private LiveData<List<RecurringTask>> upcomingRecurringTasks;
private LiveData<List<Note>> upcomingTasks;
private CustomMediatorLiveData customMediatorLiveData;
private NoteDatabase noteDatabase;
public NoteRepository(Context context) {
noteDatabase = NoteDatabase.getInstance(context);
recurringDao = noteDatabase.recurringDao();
upcomingRecurringTasks = recurringDao.getUpcomingRecurringTask();
upcomingTasks = noteDatabase.daoAccess().fetchUpcomingTasks();
this.context = context;
customMediatorLiveData = new CustomMediatorLiveData(upcomingTasks, upcomingRecurringTasks);
}
public LiveData<List<Object>> getCustomMediatorLiveData() {
return customMediatorLiveData;
}
public LiveData<List<RecurringTask>> getUpcomingRecurringTasks() {
return upcomingRecurringTasks;
}
public LiveData<List<Note>> fetchUpcomingTasks() {
return NoteDatabase.getInstance(context).daoAccess().fetchUpcomingTasks();
}
}
我尝试使用该MediatorLiveData
对象并将两个LiveData
源添加到存储库本身中,但同样的问题仍然存在。
实现这一点的正确方法是什么?如何将 2 LiveData
s 组合成一个LiveData
可以观察到的单个。