3

我正在尝试在两个表(角色和能力)之间建立关系,但是当我运行allowTo()它说是undefined的函数时。我试图清除缓存和配置,但没有做任何事情。如果有人能帮忙就太好了,谢谢!

型号

<?php

namespace App;

use Illuminate\Database\Eloquent\Model;

class Role extends Model
{
    
protected $guarded = [];

    public function abilities(){
        return $this->belongsToMany(Ability::class)->withTimestamps();
    }

   public function allowTo($ability){

        $this->abilities()->save($ability);
   }

外壳上的修补程序环境

>>> $user = App\User::find(7);

=> App\User {#3044
     id: 7,
     name: "Rebeca Tejedor",
     email: "rebtej@gmal.com",
     email_verified_at: null,
     created_at: "2020-08-13 10:29:46",
     updated_at: "2020-08-13 10:29:46",
   }
>>> $role = Role::firstOrCreate(['name'=> 'lender']);

[!] Aliasing 'Role' to 'App\Role' for this Tinker session.
=> App\Role {#3041
     id: 1,
     name: "lender",
     created_at: "2020-08-13 10:41:15",
     updated_at: "2020-08-13 10:41:15",
   }
>>> $ability = Ability::firstOrCreate(['name'=> 'edit_items']);

[!] Aliasing 'Ability' to 'App\Ability' for this Tinker session.
=> App\Ability {#3040
     id: 1,
     name: "edit_items",
     created_at: "2020-08-13 10:43:34",
     updated_at: "2020-08-13 10:43:34",
   }

>>> $role = allowTo($ability)

错误:

PHP Fatal error: Call to undefined function allowTo() in Psy Shell code on line 1

该模型

修补程序环境

4

1 回答 1

3

您正在以这种方式使用您的关系:

$role = allowTo($ability);

而你应该像这样使用它:

$role->allowTo($ability);

并在您的方法中:

public function allowTo($ability) {
    $this->abilities()->attach($ability->id);
}
于 2020-08-13T11:36:30.910 回答