3

因此，在完成了一本入门书之后，我正在尝试一些 C++，但我已经陷入困境。我制作了一个对象向量，每个对象都有一个 SFML 圆对象作为成员，我希望 main() 去绘制这些圆。该向量被称为theBoard，但是当我尝试访问它时，我收到以下错误消息：

error: request for member 'theBoard' in 'GameBoard', which is of non-class type 'Board*'
error: 'theBoard' was not declared in this scope

我是新手（来自两年的 Python），所以我确定我在某个地方犯了错误。以下是创建板的相关代码：

class Board
{
public:
    //These are the member functions.
    Board();
    ~Board();
    vector<Space*> CreateBoard();
    //This will be the game board.
    vector<Space*> theBoard;
    //These clusters represent the waiting areas for pieces not yet in the game.
    vector<Space*> Cluster1;
    vector<Space*> Cluster2;
    vector<Space*> Cluster3;
private:
    //These integers represent the number of spaces on each row, starting at the top     (which is row [0])
    vector<int> RowNums;
};

Board::Board()
{
    //Fill in RowNums with the right values.
    RowNums.push_back(1);
    RowNums.push_back(17);
    RowNums.push_back(2);
    RowNums.push_back(17);
    RowNums.push_back(1);
    RowNums.push_back(1);
    RowNums.push_back(5);
    RowNums.push_back(2);
    RowNums.push_back(7);
    RowNums.push_back(2);
    RowNums.push_back(11);
    RowNums.push_back(3);
    RowNums.push_back(17);
    RowNums.push_back(4);
    RowNums.push_back(17);
    //Then, create the board.
    theBoard = CreateBoard();
}

CreateBoard() 是一个非常非常长的函数，它返回指向 Space 对象的指针向量。我怀疑这里有问题，因为当我尝试访问 main() 中 Space 对象的圆成员时，我得到的唯一错误消息突然出现。在我看来，好像我已经theBoard在相关范围内声明了，即作为 Board 类的数据成员。

我的 main() 函数，以防它很重要：

int main()
{
    //This sets up the display window.
    sf::RenderWindow App(sf::VideoMode(1200, 900, 32), "Malefiz");

    //This creates the board on the heap, and a pointer to it.
    Board* GameBoard = new Board();

    cout << "Board made.";

    //This is the game loop.
    while(App.IsOpened())
    {
        //This is used to poll events.
        sf::Event Event;
        while(App.GetEvent(Event))
        {
            //This closes the window.
            if(Event.Type == sf::Event::Closed)
            {
                App.Close();
            }
        }

        //This gets the time since the last frame.
        //float ElapsedTime = App.GetFrameTime();

        //This fills the window with black.
        App.Clear(sf::Color(200, 200, 125));
        //This draws the places into the window.
        for(int i = 0; i < GameBoard.theBoard.size(); ++i)
        {
            App.Draw(GameBoard.*theBoard[i].m_Circle);
        }
        //This displays the window.
        App.Display();
    }

    return EXIT_SUCCESS;
}
4

4 回答 4

6

在您的main()函数中，GameBoard是 a Board *，而不是 a Board。因此，要访问成员，您需要使用->而不是.. 例如：

GameBoard->theBoard.size()

[有些人（我就是其中之一）喜欢用前导p或ptr前缀来命名他们的指针变量，以明确表达这种刺激。]

于 2011-06-13T18:11:19.033 回答
4

GameBoard 是一个指向 Board 对象的指针，因此您需要使用“->”运算符而不是“.”。运算符访问其任何成员变量或方法。

于 2011-06-13T18:12:22.693 回答
3

GameBoard是一个指针，所以语法应该是这样的：

 for(int i = 0; i < GameBoard->theBoard.size(); ++i)
 {
        App.Draw((GameBoard->theBoard[i])->m_Circle);
 }

由于theBoard也的元素是指针，所以我在访问时使用了指针表示法m_Circle。

于 2011-06-13T18:11:37.227 回答
3

如果您仔细阅读，该错误非常明显：

error: request for member 'theBoard' in 'GameBoard', which is of non-class type 'Board*'
error: 'theBoard' was not declared in this scope

第一行告诉你你有一个指向Board对象的指针，你正试图直接访问一个成员。那是：

Board *p = ...
p.theBoard;     // Error, should be p->theBoard, as p is a pointer

另请注意，这GameBoard.*theBoard[i].m_Circle可能不是您想要的，您可能想要（我猜是因为缺少重要的位）之类的东西GameBoard->theBoard[i]->m_Circle。

于 2011-06-13T18:11:47.027 回答