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在 Spring Boot 2 JPA 中，我有以下两个多对多实体。

1- 劳动力：

@Entity
public class Labor {

    @Id
    @GeneratedValue(strategy = GenerationType.IDENTITY)
    private long id;
    @Column(length = 100, nullable = false)
    private String name;
    @Column(length = 50)
    private String mobile;
    private Date dateOfBirth;
    private boolean male;
    private boolean active;
    private String brife;
    @Column(length = 500)
    private String specifcation;
    @ManyToMany(cascade = CascadeType.ALL)
    @JoinTable(name = "labor_tag",
            joinColumns = @JoinColumn(name = "labor_id"),
            inverseJoinColumns = @JoinColumn(name = "tag_id"))
    private Set<Tag> tags = new HashSet<>();
}

和标签表：

@Entity
public class Tag {

    @Id
    @GeneratedValue(strategy = GenerationType.IDENTITY)
    private long id;
    @Column(length = 100, unique = true)
    private String name;
    private boolean active = true;
    @ManyToMany(cascade = CascadeType.ALL, mappedBy = "tags")
    @JsonIgnore
    private Set<Labor> labors = new HashSet<>();
}

然后我定义了Labor Repository 来查询具有特定标签ID、性别或年龄的Labor

@Repository
public interface LaborReoistory extends JpaRepository<Labor, Long> {

    @Query("select l from Labor l join l.tags t where (:tid is null or t.id in :tid) and " +
            "(:isMale is null or :isMale = TRUE) and " +
            "((:startYear is null or :endYear is null or :startYear >  :endYear) or year(l.dateOfBirth) >= :startYear and year(l.dateOfBirth) <= :endYear)")
    Page<Labor> findLaborsByCondition(@Param("tid") final long[] tid,
                                      @Param("isMale") final Boolean isMale,
                                      @Param("startYear") final Integer startYear,
                                      @Param("endYear") final Integer endYear,
                                      final Pageable pageable);

}

当我在控制器中使用此存储库时，我发现 Pagable 的totalElements属性返回计数到labour_tag中的记录（在本例中为 16 条记录），但我真正想要的是在给定条件下让totalElements 计数。JPA Pagable 是否支持此类查询或如何找到解决方法？

谢谢

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1 回答 1

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加入后会有重复Labor，但是totalElements是使用查询的总行数。所以你应该使用DistinctonLabour来获得不同劳动力的数量

@Query("select distinct l from Labor l join l.tags t where (:tid is null or t.id in :tid) and " +
            "(:isMale is null or :isMale = TRUE) and " +
            "((:startYear is null or :endYear is null or :startYear >  :endYear) or year(l.dateOfBirth) >= :startYear and year(l.dateOfBirth) <= :endYear)")
于 2020-08-10T06:46:28.293 回答