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我需要提取邮政编码的第一部分以使用数据库进行搜索计算。有任何想法吗?!我需要这个来在站点中实现一个搜索模块,该模块根据邮政编码查找一些相关信息。但是我拥有的邮政编码数据库,它没有邮政编码的第二部分,只有第一部分在那里。它适用于英国邮政编码。那么,有什么想法吗?!

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1 回答 1

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这不会覆盖所有可能的英国邮政编码的 100%,但会覆盖 99.999% 左右:)

/**
 * @param string $postcode UK Postcode
 * @return string
 */
function getUKPostcodeFirstPart($postcode)
{
    // validate input parameters
    $postcode = strtoupper($postcode);

    // UK mainland / Channel Islands (simplified version, since we do not require to validate it)
    if (preg_match('/^[A-Z]([A-Z]?\d(\d|[A-Z])?|\d[A-Z]?)\s*?\d[A-Z][A-Z]$/i', $postcode))
        return preg_replace('/^([A-Z]([A-Z]?\d(\d|[A-Z])?|\d[A-Z]?))\s*?(\d[A-Z][A-Z])$/i', '$1', $postcode);
    // British Forces
    if (preg_match('/^(BFPO)\s*?(\d{1,4})$/i', $postcode))
        return preg_replace('/^(BFPO)\s*?(\d{1,4})$/i', '$1', $postcode);
    // overseas territories
    if (preg_match('/^(ASCN|BBND|BIQQ|FIQQ|PCRN|SIQQ|STHL|TDCU|TKCA)\s*?(1ZZ)$/i', $postcode))
        return preg_replace('/^([A-Z]{4})\s*?(1ZZ)$/i', '$1', $postcode);

    // well ... even other form of postcode... return it as is
    return $postcode;
}

测试数据:

echo 'TW135BQ -> ', getUKPostcodeFirstPart('TW135BQ'), "\n";
echo 'gir0aa -> ', getUKPostcodeFirstPart('gir0aa'), "\n";
echo 'RG5 3SQ -> ', getUKPostcodeFirstPart('RG5 3SQ'), "\n";
echo 'AB51 0GQ -> ', getUKPostcodeFirstPart('AB51 0GQ'), "\n";
echo 'YO104EA -> ', getUKPostcodeFirstPart('YO104EA'), "\n";
echo 'SE154NS -> ', getUKPostcodeFirstPart('SE154NS'), "\n";
echo 'W1B4BD -> ', getUKPostcodeFirstPart('W1B4BD'), "\n";

结果:

TW135BQ -> TW13
gir0aa -> GIR0AA
RG5 3SQ -> RG5
AB51 0GQ -> AB51
YO104EA -> YO10
SE154NS -> SE15
W1B4BD -> W1B

请注意:您有责任提供有效的邮政编码。

编辑:哎呀,它不包括 GIR 0AA,对不起

于 2011-06-11T20:45:09.533 回答