mysql - 操作数应包含 1 列 - MySQL NOT IN

Question

SELECT * from campaigns WHERE id not in
(SELECT 
    e.id_campaign, d.name, d.frequency, d.country, d.referral, d.bid, d.status, COUNT(e.id) AS countcap  
    FROM campaigns d
    LEFT JOIN served e
    ON d.id = e.id_campaign 
    WHERE 
        d.status = 'Active'
    GROUP BY e.id_campaign
    HAVING
        countcap < d.frequency)

我收到错误“操作数应包含 1 列”-但我需要 COUNT(e.id)

Answer 1

总有这样的：

select *
from campaigns 
where id not in (
    select id_campaign from (
        select e.id_campaign as id_campaign, d.frequency, e.id
        from campaigns d left join served e on d.id = e.id_campaign
        where d.status = 'Active'
        group by e.id_campaign 
        having count(e.id) < d.frequency 
    )
)

Answer 2

'not in' 子句需要一个值列表。因此，如下查询将起作用：

SELECT * from campaigns WHERE id not in
(SELECT 
    e.id_campaign
    FROM campaigns d
    LEFT JOIN served e
    ON d.id = e.id_campaign 
    WHERE 
        d.status = 'Active'
    GROUP BY e.id_campaign
    HAVING
        COUNT(e.id) < d.frequency)

如果您能告诉我们表格的结构以及您想要选择的内容，我们将能够为您找出正确的查询。

Answer 3

SELECT * from campaigns WHERE id not in
(SELECT 
e.id_campaign, d.name, d.frequency, d.country, d.referral, d.bid, d.status, 
COUNT(e.id) AS countcap  
FROM campaigns d....
)

您正在检查id 而不是这样，您应该只检查一列的检查 id。

你可以这样写（它可能无法实现你的目的）：

SELECT * from campaigns WHERE id not in
(SELECT 
e.id_campaign from campaigns d
LEFT JOIN served e
ON d.id = e.id_campaign 
WHERE 
    d.status = 'Active'
GROUP BY e.id_campaign
HAVING
    countcap < d.frequency
)