126

如果不修改android API，这可能吗？我找到了一篇关于这个的文章。有一条评论说我应该对 android API 进行修改。但它没有说明如何进行修改。谁能给我一些关于如何做到这一点的建议？谢谢！

我找到了这篇文章； SpeechRecognizer 他的需求和我的差不多。对我来说是一个很好的参考！

我已经完全解决了这个问题。我从这个中国网站
搜索了一个可用的示例代码 这是我的源代码

package voice.recognition.test;

import android.app.Activity;
import android.content.Intent;
import android.os.Bundle;
import android.view.View;
import android.view.View.OnClickListener;
import android.speech.RecognitionListener;
import android.speech.RecognizerIntent;
import android.speech.SpeechRecognizer;
import android.widget.Button;
import android.widget.TextView;
import java.util.ArrayList;
import android.util.Log;



public class voiceRecognitionTest extends Activity implements OnClickListener 
{

   private TextView mText;
   private SpeechRecognizer sr;
   private static final String TAG = "MyStt3Activity";
   @Override
   public void onCreate(Bundle savedInstanceState) 
   {
            super.onCreate(savedInstanceState);
            setContentView(R.layout.main);
            Button speakButton = (Button) findViewById(R.id.btn_speak);     
            mText = (TextView) findViewById(R.id.textView1);     
            speakButton.setOnClickListener(this);
            sr = SpeechRecognizer.createSpeechRecognizer(this);       
            sr.setRecognitionListener(new listener());        
   }

   class listener implements RecognitionListener          
   {
            public void onReadyForSpeech(Bundle params)
            {
                     Log.d(TAG, "onReadyForSpeech");
            }
            public void onBeginningOfSpeech()
            {
                     Log.d(TAG, "onBeginningOfSpeech");
            }
            public void onRmsChanged(float rmsdB)
            {
                     Log.d(TAG, "onRmsChanged");
            }
            public void onBufferReceived(byte[] buffer)
            {
                     Log.d(TAG, "onBufferReceived");
            }
            public void onEndOfSpeech()
            {
                     Log.d(TAG, "onEndofSpeech");
            }
            public void onError(int error)
            {
                     Log.d(TAG,  "error " +  error);
                     mText.setText("error " + error);
            }
            public void onResults(Bundle results)                   
            {
                     String str = new String();
                     Log.d(TAG, "onResults " + results);
                     ArrayList data = results.getStringArrayList(SpeechRecognizer.RESULTS_RECOGNITION);
                     for (int i = 0; i < data.size(); i++)
                     {
                               Log.d(TAG, "result " + data.get(i));
                               str += data.get(i);
                     }
                     mText.setText("results: "+String.valueOf(data.size()));        
            }
            public void onPartialResults(Bundle partialResults)
            {
                     Log.d(TAG, "onPartialResults");
            }
            public void onEvent(int eventType, Bundle params)
            {
                     Log.d(TAG, "onEvent " + eventType);
            }
   }
   public void onClick(View v) {
            if (v.getId() == R.id.btn_speak) 
            {
                Intent intent = new Intent(RecognizerIntent.ACTION_RECOGNIZE_SPEECH);        
                intent.putExtra(RecognizerIntent.EXTRA_LANGUAGE_MODEL,RecognizerIntent.LANGUAGE_MODEL_FREE_FORM);
                intent.putExtra(RecognizerIntent.EXTRA_CALLING_PACKAGE,"voice.recognition.test");

                intent.putExtra(RecognizerIntent.EXTRA_MAX_RESULTS,5); 
                     sr.startListening(intent);
                     Log.i("111111","11111111");
            }
   }
}

调试后一定要删除烦人的Logs！

4

4 回答 4

74

使用SpeechRecognizer接口。你的应用需要有 RECORD_AUDIO 权限，然后你可以创建一个 SpeechRecognizer，给它一个RecognitionListener，然后调用它的startListening方法。当语音识别器准备好开始收听语音并接收语音并将其转换为文本时，您将收到对听众的回调。

于 2011-06-11T16:18:40.097 回答
7

GAST有一个方便的抽象类，您可以使用SpeechRecognizer该类来使用很少的新代码。还有一个使用this和thisSpeechRecognizer作为后台服务运行的示例

于 2012-06-11T09:20:47.023 回答
6

感谢您发布此信息！我发现在 oncreate 中定义 onclick 监听器很有帮助：

@Override
protected void onCreate(Bundle savedInstanceState) {
    super.onCreate(savedInstanceState);
    setContentView(R.layout.activity_main);

    mText = (TextView) findViewById(R.id.textView1);     
    MyRecognitionListener listener = new MyRecognitionListener();
    sr = SpeechRecognizer.createSpeechRecognizer(this);       
    sr.setRecognitionListener(listener);

    findViewById(R.id.button1).setOnClickListener( new View.OnClickListener() {
        @Override
        public void onClick(View v) 
        {
                Intent intent = new Intent(RecognizerIntent.ACTION_RECOGNIZE_SPEECH);    
                intent.putExtra(RecognizerIntent.EXTRA_LANGUAGE_MODEL, "en-US");
                intent.putExtra(RecognizerIntent.EXTRA_MAX_RESULTS,1); 
                intent.putExtra(RecognizerIntent.EXTRA_CALLING_PACKAGE,"voice.recognition.test");
                sr.startListening(intent);
        }
    });     
}
于 2013-07-21T00:30:32.947 回答
4

我最终制作了 Github 项目，将文本转换为语音，将语音转换为文本，而无需烦人的对话，

https://github.com/hiteshsahu/Android-TTS-STT/tree/master/app/src/main/java/com/hiteshsahu/stt_tts/translation_engine

 //SPEECH TO TEXT DEMO
    speechToText.setOnClickListener({ view ->

        Snackbar.make(view, "Speak now, App is listening", Snackbar.LENGTH_LONG)
                .setAction("Action", null).show()

        TranslatorFactory
                .instance
                .with(TranslatorFactory.TRANSLATORS.SPEECH_TO_TEXT,
                        object : ConversionCallback {
                            override fun onSuccess(result: String) {
                                sttOutput.text = result
                            }

                            override fun onCompletion() {
                            }

                            override fun onErrorOccurred(errorMessage: String) {
                                erroConsole.text = "Speech2Text Error: $errorMessage"
                            }

                        }).initialize("Speak Now !!", this@HomeActivity)

    })


    //TEXT TO SPEECH DEMO
    textToSpeech.setOnClickListener({ view ->

        val stringToSpeak :String = ttsInput.text.toString()

        if (null!=stringToSpeak &&  stringToSpeak.isNotEmpty()) {

            TranslatorFactory
                    .instance
                    .with(TranslatorFactory.TRANSLATORS.TEXT_TO_SPEECH,
                            object : ConversionCallback {
                                override fun onSuccess(result: String) {
                                }

                                override fun onCompletion() {
                                }

                                override fun onErrorOccurred(errorMessage: String) {
                                    erroConsole.text = "Text2Speech Error: $errorMessage"
                                }

                            })
                    .initialize(stringToSpeak, this)

        } else {
            ttsInput.setText("Invalid input")
            Snackbar.make(view, "Please enter some text to speak", Snackbar.LENGTH_LONG).show()
        }

    })

在此处输入图像描述

于 2016-07-13T03:23:36.550 回答