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所以我有这个运行良好的查询，但我需要在其他几个领域使用工厂标准成本，所以我没有多次调用该函数，而是将它放在外部应用中。但是，它现在似乎不起作用。我收到以下错误：

在包含外部引用的聚合表达式中指定了多个列。如果要聚合的表达式包含外部引用，则该外部引用必须是表达式中引用的唯一列。

这是工作查询：

SELECT
    DISTINCT ap.[SourcePartID] AS [Assembly Part ID],
    p.[PART_X] AS [Assembly Part #],
    p.[DESCR_X] AS [Assembly Part Description],
    oa2.[Part Count],
    oa2.[Total # of Parts],
    ([dbo].[fn_getFactoryStdCost](ap.[SourcePartID])) AS [Factory Std Cost],
    oa2.[# of Docs],
    oa2.[# of Software],
    'Logic Pending' AS [# of Std Cost Items],
    oa2.[# of HR Devices],
    oa2.[# of 3rd Party Devices],
    oa2.[# of Robots],
    oa2.[# of Buy Parts],
    oa2.[# of Make Parts]

  FROM AllPartsList ap
    LEFT JOIN visuser.EN_PART p
      ON p.[EN_Part_ID] = ap.[SourcePartID]
    OUTER APPLY (
        SELECT
            [Part Count]                = COUNT(    DISTINCT IIF( [Qty] = 0, null, [Component Part #])  ),  
            [Total # of Parts]          = SUM([Qty]),
            [# of Docs]                 = COUNT(    DISTINCT IIF( [Commodity Code] IN ('009', '072', '073', '075', '079', '082'), [Component Part #], null) ),  -- Commodity Codes: 009, 072, 073, 075, 079, 082  :  Commodity ID: 15, 84, 85, 87, 81, 92
            [# of Software]             = COUNT(    DISTINCT IIF( [Commodity Code] IN ('034'), [Component Part #], null)    ),                                  -- Commodity Code 034  :  Commodity ID: 28
            [# of HR Devices]           = COUNT(    DISTINCT IIF( [Commodity Code] IN ('002'), [Component Part #], null)    ),                                  -- Commodity Code 002  :  Commodity ID: 11
            [# of 3rd Party Devices]    = COUNT(    DISTINCT IIF( [Commodity Code] IN ('007'), [Component Part #], null)    ),                                  -- Commodity Code 007  :  Commodity ID: 5
            [# of Robots]               = COUNT(    DISTINCT IIF( ( [Commodity Code] IN ('005') /* AND [Make/Buy] = 'B' */ ), [Component Part #], null) )   ,       -- Commodity Code 005  :  Commodity ID: 13
            [# of Make Parts]           = COUNT(    DISTINCT IIF( [Make/Buy] = 'M', [Component Part #], null)   ),
            [# of Buy Parts]            = COUNT(    DISTINCT IIF( [Make/Buy] = 'B', [Component Part #], null)   ),
            [# of Ref Parts]            = COUNT(    DISTINCT IIF( [Make/Buy] = 'B', [Component Part #], null)   )
            
          FROM bomBreakdown
          WHERE
            [ComponentPartID] IS NOT NULL AND 
            [SourcePartID] = ap.[SourcePartID]
          GROUP BY [SourcePartID]
    ) oa2
    ORDER BY [PART_X]

这是我将其更改为的内容。我将对函数的调用移至外部应用，并在主查询和第二个外部应用中使用它。该错误引用了第二个外部应用的第一行，其中oa1.[Factory Std Cost]

SELECT
    DISTINCT ap.[SourcePartID] AS [Assembly Part ID],
    p.[PART_X] AS [Assembly Part #],
    p.[DESCR_X] AS [Assembly Part Description],
    oa2.[Part Count],
    oa2.[Total # of Parts],
    oa1.[Factory Std Cost], 
    oa2.[# of Docs],
    oa2.[# of Software],
    'Logic Pending' AS [# of Std Cost Items],
    oa2.[# of HR Devices],
    oa2.[# of 3rd Party Devices],
    oa2.[# of Robots],
    oa2.[# of Buy Parts],
    oa2.[# of Make Parts]

  FROM AllPartsList ap
    LEFT JOIN visuser.EN_PART p
      ON p.[EN_Part_ID] = ap.[SourcePartID]
    OUTER APPLY (
      SELECT ([dbo].[fn_getFactoryStdCost](ap.[SourcePartID])) AS [Factory Std Cost]
    ) oa1
    OUTER APPLY (
        SELECT
            [Part Count]                = COUNT(    DISTINCT IIF( [Qty] = 0, null, [Component Part #])  ),  
            [Total # of Parts]          = SUM([Qty]),
            [# of Docs]                 = COUNT(    DISTINCT IIF( [Commodity Code] IN ('009', '072', '073', '075', '079', '082'), [Component Part #], null) ),  -- Commodity Codes: 009, 072, 073, 075, 079, 082  :  Commodity ID: 15, 84, 85, 87, 81, 92
            [# of Software]             = COUNT(    DISTINCT IIF( [Commodity Code] IN ('034'), [Component Part #], null)    ),                                  -- Commodity Code 034  :  Commodity ID: 28
            [# of HR Devices]           = COUNT(    DISTINCT IIF( ( [Commodity Code] IN ('002') AND oa1.[Factory Std Cost] > 0 ), [Component Part #], null) ),                                  -- Commodity Code 002  :  Commodity ID: 11
            [# of 3rd Party Devices]    = COUNT(    DISTINCT IIF( [Commodity Code] IN ('007'), [Component Part #], null)    ),                                  -- Commodity Code 007  :  Commodity ID: 5
            [# of Robots]               = COUNT(    DISTINCT IIF( ( [Commodity Code] IN ('005') /* AND [Make/Buy] = 'B' */ ), [Component Part #], null) )   ,       -- Commodity Code 005  :  Commodity ID: 13
            [# of Make Parts]           = COUNT(    DISTINCT IIF( ( [Make/Buy] = 'M' AND oa1.[Factory Std Cost] > 0 ), [Component Part #], null)    ),
            [# of Buy Parts]            = COUNT(    DISTINCT IIF( ( [Make/Buy] = 'B' AND oa1.[Factory Std Cost] > 0 ), [Component Part #], null)    ),
            [# of Ref Parts]            = COUNT(    DISTINCT IIF( ( [Make/Buy] = 'B' AND oa1.[Factory Std Cost] = 0 ), [Component Part #], null)    )
            
          FROM bomBreakdown
          WHERE
            [ComponentPartID] IS NOT NULL AND 
            [SourcePartID] = ap.[SourcePartID]
          GROUP BY [SourcePartID]
    ) oa2
    ORDER BY [PART_X]

这是 AllPartsList 的样子： 所有零件清单表

和 bomBreakdown： bom分解表

我恢复了查询，然后尝试一次添加一些内容，以查看出错的确切位置。我添加了[# of Ref Parts]仅使用 Make/But = 'B' 的行（它与 Buy Parts 基本相同）。在我为 stdCost 添加函数之前，它运行良好。然后我收到了相同的外部参考错误。这是一行：

COUNT(  DISTINCT IIF( ( [Make/Buy] = 'B' AND ([dbo].[fn_getFactoryStdCost](ap.[SourcePartID])) = 0 ), [Component Part #], null) )

经过一番玩弄后，我发现问题出ap.[SourcePartID]在对函数的调用中。这是链接 AllPartsList 和 bomBreakdown 表的关键字段，因此我可以删除ap.并只使用 bomBreakdown 表中的那个，但它并没有解决我首先尝试解决的不调用函数的问题多次。

我正在使用：

  • SQL Server 2019 (v15.0.2070.41)
  • SSMS v18.5
4

1 回答 1

1

如错误消息所示，您不能在聚合内引用 OUTER 列。你可以自己尝试一个小例子，你会发现 MS SQL 不允许这样做。这是一个想法，其中外部引用通过 OUTER 子查询中的附加 JOIN 转换为内部引用

错误：“在包含外部引用的聚合表达式中指定了多个列。”

于 2020-07-28T07:33:13.477 回答