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我想玩一下hibernate、panache和quarkus。我想构建一个“跟踪”api，一个人可以有多个跟踪，但一个跟踪只能由一个人拥有。但我面临反序列化错误。

假设我想发布这个：

curl --location --request POST 'localhost:8080/trace' \
--header 'Content-Type: application/json' \
--data-raw '{
    "traceOwner": "AtestOwner",
    "participants": ["Karl", "John"],
    "place": "10101, TestCity, TestStreet 25",
    "startTime": "2016-07-20T23:07:41.907+02:00[Europe/Berlin]",
    "stopTime": "2016-07-27T23:07:45.807+02:00",
    "comment": "TestComment"
}'

我收到以下错误：

javax.ws.rs.ProcessingException: RESTEASY008200: JSON Binding deserialization error: javax.json.bind.JsonbException:
Unable to deserialize property 'traceOwner' because of: Error deserialize JSON value into type: class
de.test.Person.

并在日志中：

2020-07-27 10:48:12,597 SEVERE [org.ecl.yas.int.Unmarshaller] (executor-thread-1) Unable to deserialize property 'traceOwner' because of: Error deserialize JSON value into type: class de.test.Person.

我的实体看起来像这样：

import java.time.ZonedDateTime;
import java.util.List;

import javax.persistence.Column;
import javax.persistence.ElementCollection;
import javax.persistence.Entity;
import javax.persistence.ManyToOne;

import io.quarkus.hibernate.orm.panache.PanacheEntity;

@Entity
public class Trace extends PanacheEntity {
  @ManyToOne
  public Person traceOwner;
  @ElementCollection
  public List<String> participants;
  public String place;
  @Column(columnDefinition = "TIMESTAMP WITH TIME ZONE")
  public ZonedDateTime startTime;
  @Column(columnDefinition = "TIMESTAMP WITH TIME ZONE")
  public ZonedDateTime stopTime;
  public String comment;

  public String toString() {
    return String.format("%s, [%s, %s], %s, %s, %s", this.traceOwner, this.participants.get(0),
        this.participants.get(1), this.place, this.startTime, this.stopTime, this.comment);
  }
}

和

import javax.persistence.Entity;

import io.quarkus.hibernate.orm.panache.PanacheEntity;

@Entity
public class Person extends PanacheEntity {
  public String name;
}

POST 端点如下所示：

  @POST
  @Produces(MediaType.APPLICATION_JSON)
  @Consumes(MediaType.APPLICATION_JSON)
  public Response createTrace(@Valid Trace trace) {
    try {
      LOG.info(trace);
      transaction.begin();
      trace.persist();
      transaction.commit();
    } catch (NotSupportedException | SystemException | SecurityException | IllegalStateException | RollbackException
        | HeuristicMixedException | HeuristicRollbackException e1) {
      LOG.error("Could not finish transaction to save entity", e1);
      return Response.status(HttpStatus.SC_BAD_REQUEST).build();

    }
    return Response.ok(Trace.find("startTime =?1 AND traceOwner = ?2", trace.startTime, trace.traceOwner).firstResult())
        .build();
  }

为了避免缓存问题，我打开了一个新事务，但我想这不是问题吗？

我真的不明白为什么 jsonB 抱怨反序列化以及如何修复它。此外，在某些时候我想public List<String> participants成为public List<Person> participants但可以等到关系和反序列化工作。

4

1 回答 1

2

所以，我发现我做错了什么。两件事情：

  1. 使用有效的 json：
curl --location --request POST 'localhost:8080/trace' \
--header 'Content-Type: application/json' \
--data-raw '{
    "traceOwner": {"name": "AtestOwner"},
    "participants": ["Karl", "John"],
    "place": "10101, TestCity, TestStreet 25",
    "startTime": "2016-07-20T23:07:41.907+02:00[Europe/Berlin]",
    "stopTime": "2016-07-27T23:07:45.807+02:00",
    "comment": "TestComment"
}'

请注意不同的“traceOwner”部分。

  1. 用于@ManyToOne(cascade = CascadeType.ALL)在持久化时更新瞬态属性。
于 2020-07-27T20:40:15.760 回答