django - drf-yasg 自定义 json 正文

Question

如何在基于类的 django 视图中自定义 drf-yasg 模式？

我尝试了这部分代码，但生成的招摇不尊重更改。

class CustomView(CreateAPIView):
    permission_classes = (IsAuthenticated,)
    serializer_class = CustomSerializer

    @swagger_auto_schema(request_body=openapi.Schema(
        type=openapi.TYPE_OBJECT,
        properties={
            'phone': openapi.Schema(type=openapi.TYPE_STRING, description='string'),
            'body': openapi.Schema(type=openapi.TYPE_STRING, description='string'),
        }))
    def create(self, request: Request, *args, **kwargs):
        phone = request.data.get('phone')
        body = request.data.get('body')
        ...

Answer 1

我找到了，这是正确的代码：

class CustomView(CreateAPIView):
    permission_classes = (IsAuthenticated,)
    serializer_class = CustomSerializer
    http_method_names = ['post']

    @swagger_auto_schema(request_body=openapi.Schema(
        type=openapi.TYPE_OBJECT,
        properties={
            'phone': openapi.Schema(type=openapi.TYPE_STRING, description='The desc'),
            'body': openapi.Schema(type=openapi.TYPE_STRING, description='The desc'),
        }))
    def post(self, request: Request, *args, **kwargs):
        phone = request.data.get('phone')
        body = request.data.get('body')
        ...

对于 IN_QUERY 类型，如下所示：

class CustomListView(ListAPIView):
    permission_classes = (IsAuthenticated,)
    serializer_class = CustomSerializer
    http_method_names = ['get']

    @swagger_auto_schema(manual_parameters=[
        openapi.Parameter('obj_id', openapi.IN_QUERY,
                          type=openapi.TYPE_STRING),
    ])
    def get(self, request, *args, **kwargs):
        obj_id = self.request.DATA.get('obj_id')