2

使用带有LIKE. 例子:

$sql = " SELECT DISTINCT u.uid, u.name, u.status, u.created, u.access FROM d_bi_test_2_shared.users u LEFT JOIN d_bi_test_2.users_roles ur ON u.uid = ur.uid WHERE u.uid != 0 AND LOWER(u.name) LIKE LOWER('%%er%%') ";
$sqlCount = " SELECT COUNT(*) FROM d_bi_test_2_shared.users u LEFT JOIN d_bi_test_2.users_roles ur ON u.uid = ur.uid WHERE u.uid != 0 AND LOWER(u.name) LIKE LOWER('%%er%%') ";
$count = 3;
$query = pager_query($sql, 5, 0, $sqlCount);
$output.=theme('pager', $count);

这根本没有给我传呼机。如果我取出LIKE它,它会起作用,但我需要像这样搜索我的表格。

4

1 回答 1

0

尝试 CONCAT('%%',LOWER(er),'%%')

于 2011-08-15T03:43:05.690 回答