3

我遵循Apollo Federation的指南：实施服务

代码在这里：

import { ApolloServer, gql, IResolvers } from 'apollo-server';
import { buildFederatedSchema } from '@apollo/federation';
import faker from 'faker';

const MemoryDB = {
  users: [
    { id: 1, name: faker.name.findName() },
    { id: 2, name: faker.name.findName() },
  ],
};

const typeDefs = gql`
  type Query {
    userById(id: ID!): User
  }
  type User @key(fields: "id") {
    id: ID!
    name: String!
  }
`;

const resolvers: IResolvers = {
  Query: {
    me: (_, { id }, { db }) => {
      return db.users.find((u) => u.id === +id);
    },
  },
  User: {
    __resolveReference(user, { db }) {
      return db.users.find((u) => u.id === user.id);
    },
  },
};

const server = new ApolloServer({
  schema: buildFederatedSchema([{ typeDefs, resolvers }]), // TSC throw error here
});

TSC 抛出类型错误：

类型 'IResolvers<any, any>' 不可分配给类型 'GraphQLResolverMap'。索引签名不兼容。键入'(() => 任何) | GraphQLScalarType | IEnumResolver | IResolverObject<任何，任何，任何> | IResolverOptions<any, any, any>' 不可分配给类型 'GraphQLScalarType | { [枚举值：字符串]：字符串 | 数字; } | { [fieldName: string]: GraphQLFieldResolver<any, any, { [argName: string]: any; }> | { 需要？：字符串 | 不明确的; 解决：GraphQLFieldResolver<...>; }; }'。类型 '() => any' 不可分配给类型 'GraphQLScalarType | { [枚举值：字符串]：字符串 | 数字; } | { [fieldName: string]: GraphQLFieldResolver<any, any, { [argName: string]: any; }> | { 需要？：字符串 | 不明确的; 解决：GraphQLFieldResolver<...>; }; }'。类型 ' () => any' 不能分配给类型 '{ [fieldName: string]: GraphQLFieldResolver<any, any, { [argName: string]: any; }> | { 需要？：字符串 | 不明确的; 解析：GraphQLFieldResolver<any, any, { [argName: string]: any; }>; }; }'。'() => any'.ts(2322) 类型中缺少索引签名

软件包版本：

"apollo-server": "^2.12.0",
"@apollo/federation": "^0.17.0",

好像IResolvers接口不兼容，但是GraphQLResolverMap接口没有暴露，所以我无法导入和使用。我不想将解析器的类型强制转换为any类型。这是一个错误吗？

更新

apollo-server更新后问题依旧"apollo-server": "^2.15.1",

4

1 回答 1

1

我相信 GraphQLResolverMap 在别处，试试：

import { GraphQLResolverMap } from 'apollo-graphql';

然后使用它代替 IResolvers。

于 2021-06-18T13:29:41.270 回答