0

我将drf_yasg swagger用于我的 Django API。我想知道如何轻松禁用模式和模型。 截屏

这是我的代码:

from .models import Articles
from .serializers import ArticlesSerializer
from rest_framework import viewsets
from rest_framework.response import Response
from rest_framework import status
from rest_framework.authentication import SessionAuthentication,TokenAuthentication, BasicAuthentication
from rest_framework.views import APIView
from rest_framework.permissions import IsAuthenticated
from rest_framework.parsers import JSONParser
from django.utils.decorators import method_decorator
from django.contrib.auth import authenticate, login, logout
from rest_framework.decorators import api_view

from drf_yasg.utils import swagger_auto_schema
from drf_yasg import openapi


@swagger_auto_schema(methods=['get'], operation_description="description", manual_parameters=[
    openapi.Parameter('category', openapi.IN_QUERY, "category1, category2, category3", type=openapi.TYPE_STRING),
    openapi.Parameter('name', openapi.IN_QUERY, "full name", type=openapi.TYPE_STRING),
], responses={
    200: openapi.Response('Response', ArticlesSerializer),
}, tags=['Articles'])

# desactivate POST methode on swagger
@swagger_auto_schema(method='POST', auto_schema=None)

@api_view(['GET','POST'])   
def articles(request):
    """
    List all articles.
    """
    if request.user.is_authenticated:
        if request.method == 'GET':
            articles = Articles.objects.all()
            serializer = ArticlesSerializer(Articles, many=True)
            return JsonResponse(serializer.data, safe=False)

        elif request.method == 'POST':
            data = JSONParser().parse(request)
            serializer = ArticlesSerializer(data=data)
            if serializer.is_valid():
                serializer.save()
                return JsonResponse(serializer.data, status=201)
            return JsonResponse(serializer.errors, status=400)
    return JsonResponse({"status":"403", "message":"User not authenticated"})

如果我添加这个

class UserList(APIView):
swagger_schema = None

我得到了错误:

AssertionError: `method` or `methods` can only be specified on @action or @api_view views

代码编辑:文章功能非常简单,与 API 无关,只有 Python 代码。

这里的views 类也很简单。

类视图:

from django.db import models

class Articles(models.Model):
STATUS = (
   (1, 'PENDING'),
   (2, 'COMPLETED'),
   (3, 'DECLINED'),
   (0, 'BANNED'),
)
name = models.CharField(max_length=100)
...
status = models.PositiveSmallIntegerField(
   choices = STATUS,
   default = 1,
)
4

2 回答 2

0

我只有一半的答案,为了禁用模型,我将它添加到我的setting.py

SWAGGER_SETTINGS = {
    'DEFAULT_FIELD_INSPECTORS': [
        'drf_yasg.inspectors.CamelCaseJSONFilter',
        'drf_yasg.inspectors.InlineSerializerInspector',
        'drf_yasg.inspectors.RelatedFieldInspector',
        'drf_yasg.inspectors.ChoiceFieldInspector',
        'drf_yasg.inspectors.FileFieldInspector',
        'drf_yasg.inspectors.DictFieldInspector',
        'drf_yasg.inspectors.SimpleFieldInspector',
        'drf_yasg.inspectors.StringDefaultFieldInspector',
    ],
}

归功于这些家伙,这里是有关更多详细信息的文档

于 2020-07-20T16:18:17.743 回答
0

我终于弄明白了。我只需要用纯文本、markdown 或 html 覆盖响应参数。

@swagger_auto_schema(methods=['get'], operation_description="Get article information ", manual_parameters=[
    openapi.Parameter('id', openapi.IN_QUERY, "Article Id", type=openapi.TYPE_STRING),
], responses={ 200: '**Example:** \
  <div class="highlight-code"><pre>{  <br>\
  "category": "string", <br>\
  "image": "string",<br>\
  "link": "string",<br>\
  "birth_date": "string",<br>\
}</pre></div>'},
tags=['Get Articles'])

要获得相同的 css 效果(背景黑色),您可以在文件 ...\site-packages\drf_yasg\static\drf-yasg\style.css 中添加此自定义 CSS

.swagger-ui .markdown .highlight-code pre{
  color: #fff;
  font-weight: 400;
  white-space: pre-wrap;
  background: #41444e;
  padding: 15px;
}

在此处输入图像描述

于 2020-07-29T23:19:33.620 回答