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我的引导程序中有这个：

protected function _initAutoload()
{
    $this->_auth = Zend_Auth::getInstance();
    $this->_acl = new Federico_Plugin_Acl($this->_auth);
 ....
}
....
protected function _initNavigation()
{
    $this->bootstrap('view');

    $view = $this->getResource('view');
    $config = new Zend_Config_Xml(APPLICATION_PATH . '/configs/navigation.xml','nav');
    $navigation = new Zend_Navigation($config);
    $view->navigation($navigation)->setAcl($this->_acl)
                                  ->setRole($this->_auth->getStorage()->read()->role);//I just added this
}

然而我刚刚做的插入产生了这个：

可捕获的致命错误：传递给 Zend_View_Helper_Navigation_HelperAbstract::setAcl() 的参数 1 必须是 Zend_Acl 的实例，Federico_Plugin_Acl 的实例，在 /home/fiodorovich/public_html/gisele/application/Bootstrap.php 第 106 行调用并在 /home 中定义/fiodorovich/library/ZendFramework/library/Zend/View/Helper/Navigation/HelperAbstract.php 在第 333 行

这就是我的 navigation.xml 到目前为止的样子：

<configdata>
<nav>
    <home>
        <label>HOME</label>
        <controller>index</controller>
        <action>index</action>
    </home>
    <about>
        <label>Nosotros</label>
        <module>default</module>
        <controller>about</controller>
        <action>index</action>
    </about>
<admin>
        <label>Admin</label>
        <uri>admin/index</uri>
        <resource>admin</resource>
        <pages>
            <alta>
                <active>0</active>
                <label>Alta Usuario</label>
                <controller>users</controller>
                <action>create</action>
            </alta>    
        </pages>
    </admin>
</nav>

现在，即使是客人用户也可以看到导航中的项目，尽管他们无法访问，因为已经在 Acl 类中设置了......我如何在这里传递 acl 角色？

编辑：

//my acl
class Federico_Plugin_Acl extends Zend_Controller_Plugin_Abstract
{
private $_acl = null;
private $_auth = null;
const DEFAULT_ROLE = 'guest';

public function __construct($auth)
{
    $this->_auth = $auth;

    $this->_acl = new Zend_Acl();
    $this->_acl->addRole(new Zend_Acl_Role(self::DEFAULT_ROLE));
    $this->_acl->addRole(new Zend_Acl_Role('user'), self::DEFAULT_ROLE);
    $this->_acl->addRole(new Zend_Acl_Role('admin'), 'user');

    $this->_acl->addResource(new Zend_Acl_Resource('index'));
    $this->_acl->addResource(new Zend_Acl_Resource('users'));
    $this->_acl->addResource(new Zend_Acl_Resource('about'));
    $this->_acl->addResource(new Zend_Acl_Resource('gisele'));
    $this->_acl->addResource(new Zend_Acl_Resource('admin'));

    $this->_acl->allow('guest', 'index');
    $this->_acl->allow('guest', 'about');
    $this->_acl->deny('guest', 'gisele');
    $this->_acl->deny('guest', 'users');

    $this->_acl->allow('user', 'users', array('index')); 

    $this->_acl->allow('admin','users');
    $this->_acl->allow('admin','gisele');    
}

public function preDispatch (Zend_Controller_Request_Abstract $request)
{
    if ($this->_auth->hasIdentity()) {
        // user is logged in and we can get role
        $role = $this->_auth->getStorage()->read()->role;  
    } else {
        // guest
        $role = self::DEFAULT_ROLE;
    }
    $action = $request->getActionName();
    $controller = $request->getControllerName();
    if($this->_acl->has($controller)) {
        if(!$this->_acl->isAllowed($role, $controller, $action)) {
            $request->setActionName('error');
            $request->setControllerName('error');
        }
    }
}
}
4

1 回答 1

1

获取 Zend_View 实例（在您的引导程序中，在操作助手中，任何对您来说更容易的地方），然后：

$view->navigation()
    ->setAcl(Zend_Acl $acl)
    ->setRole(Zend_Acl_Role $role);

基本上，必须明确地为导航视图助手提供有关 ACL 和当前角色的知识。

于 2011-06-09T01:07:23.507 回答