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我正在创建倒计时来计算我打算观看的 2012 年欧洲杯比赛之间的时间。我已经提供了它的工作版本,但我不明白为什么它有时会给我带来负值。我认为这与我使用 getTime() 方法编写它的方式有关。这是我的代码,你们能帮我找出解决那些负值的方法吗?非常感谢您提前。

<body onload="timeto2012()">
<script type="text/javascript">
 function timeto2012() {
 var euro2012 = new Date(2012, 5, 10, 20, 45);
 var euro2012ms = euro2012.getTime();
var now = new Date();
var nowms = now.getTime();

var diff = euro2012ms - nowms;

var seconds = 1000;
var minutes = seconds*60;
var hours = minutes*60;
var days = hours*24;
var years = days*365;

var ddays = diff/days;
var dhours = (ddays - Math.round(ddays,1))*24;
var dminutes = (dhours - Math.round(dhours))*60;
var dseconds = (dminutes - Math.round(dminutes))*60;

document.getElementById("time").innerHTML='' + Math.round(ddays,1) +' days '+ Math.round(dhours,1) +' hours '+ Math.round(dminutes,1) +' minutes '+ Math.round(dseconds,1) + ' seconds remaining';

}

t=setInterval(timeto2012,500);

</script>   
<div id="time"></div>
</body>
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2 回答 2

1

KOGI 为您的问题提供了答案:您应该使用Math.floor而不是Math.round

当还剩 x 分 30 - 59 秒时,(x - Math.round(x))相当于(x - (x + 1))舍入完成后。

var ddays = diff/days;
var dhours = (ddays - Math.floor(ddays))*24;
var dminutes = (dhours - Math.floor(dhours))*60;
var dseconds = (dminutes - Math.floor(dminutes))*60;

小提琴:http: //jsfiddle.net/YHktx/3/

于 2011-06-08T17:40:06.700 回答
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这里有一些更好的计算方法(来自 Aleksi Yrttiaho 的 jsFiddle)

var seconds = 1000;
var minutes = seconds*60;
var hours = minutes*60;
var days = hours*24;
var years = days*365;

var ddays = Math.floor( diff/days );
var dhours = Math.floor((diff % days) / hours );
var dminutes = Math.floor(((diff % days) % hours) / minutes );
var dseconds = Math.floor((((diff % days) % hours) % minutes) / seconds );
于 2011-06-08T17:34:56.887 回答