7
class RegistrationFormPreview(FormPreview):
    preview_template    = 'workshops/workshop_register_preview.html'
    form_template       = 'workshops/workshop_register_form.html'

    def done(self, request, cleaned_data):
        # Do something with the cleaned_data, then redirect
        # to a "success" page. 
        # data = request.POST.copy()
        # data['user_id'] = u'%s' % (request.user.id)
        # cleaned_data['user'] = u'%s' % (request.user.id)
        #f = self.form(cleaned_data)
        #f = self.form(data)
        #f.user = request.user


        f = self.form(request.POST)
        f.save()

        pdb.set_trace()
        return HttpResponseRedirect('/register/success')

如您所见,我尝试了几种方法,并且已被注释掉。任务显然很简单:在保存之前将用户从请求添加到表单,然后保存。

这里接受的工作方法是什么?

4

1 回答 1

12

如果无法修改用户,我会说它甚至不应该首先包含在表单中。

无论哪种方式,使用commit参数来防止立即保存生成的对象应该可以工作(假设FormPreview使用ModelForm):

obj = form.save(commit=False)
obj.user = request.user
obj.save()
于 2009-03-09T11:06:32.323 回答