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如何在return子句中混合“新”标签xquery

这是我所追求的输出形式:

<?xml version="1.0"?>
<csv>
  <record>
    <sex>M</sex>
  </record>
  <record>
    <sex>F</sex>
  </record>
  <record>
    <sex>M</sex>
  </record>
  <record>
    <sex>F</sex>
  </record>
</csv>

我刚刚手动输入的具体值用于说明目的。实际值和电流输出为:

<?xml version="1.0" encoding="UTF-8"?><csv>SexMFFMFFMF</csv>

原始xml数据:

<csv>
  <record>
    <entry>Reported_Date</entry>
    <entry>HA</entry>
    <entry>Sex</entry>
    <entry>Age_Group</entry>
    <entry>Classification_Reported</entry>
  </record>
  <record>
    <entry>2020-01-26</entry>
    <entry>Vancouver Coastal</entry>
    <entry>M</entry>
    <entry>40-49</entry>
    <entry>Lab-diagnosed</entry>
  </record>
  <record>
    <entry>2020-02-02</entry>
    <entry>Vancouver Coastal</entry>
    <entry>F</entry>
    <entry>50-59</entry>
    <entry>Lab-diagnosed</entry>
  </record>
  <record>
    <entry>2020-02-05</entry>
    <entry>Vancouver Coastal</entry>
    <entry>F</entry>
    <entry>20-29</entry>
    <entry>Lab-diagnosed</entry>
  </record>
  <record>
    <entry>2020-02-05</entry>
    <entry>Vancouver Coastal</entry>
    <entry>M</entry>
    <entry>30-39</entry>
    <entry>Lab-diagnosed</entry>
  </record>
  <record>
    <entry>2020-02-11</entry>
    <entry>Interior</entry>
    <entry>F</entry>
    <entry>30-39</entry>
    <entry>Lab-diagnosed</entry>
  </record>
  <record>
    <entry>2020-02-20</entry>
    <entry>Fraser</entry>
    <entry>F</entry>
    <entry>30-39</entry>
    <entry>Lab-diagnosed</entry>
  </record>
  <record>
    <entry>2020-02-21</entry>
    <entry>Fraser</entry>
    <entry>M</entry>
    <entry>40-49</entry>
    <entry>Lab-diagnosed</entry>
  </record>
  <record>
    <entry>2020-02-27</entry>
    <entry>Vancouver Coastal</entry>
    <entry>F</entry>
    <entry>60-69</entry>
    <entry>Lab-diagnosed</entry>
  </record>
</csv>

FLWOR查询:

declare namespace map = "http://www.w3.org/2005/xpath-functions/map";
declare namespace array = "http://www.w3.org/2005/xpath-functions/array";

declare namespace output = "http://www.w3.org/2010/xslt-xquery-serialization";

for $x in /csv

return <csv>{$x/record[position() = (1 to 9)]/entry[3]/text()}</csv>

我尝试将节点标签放在大括号内,但遇到语法错误。

4

1 回答 1

1

使用例如

<csv>
{
for $record in /csv/record[position() = (2 to 9)]
return
  <record>
    <sex>{data($record/entry[3])}</sex>
  </record>
}
</csv>

或简单的地图运算符

<csv>
{
  /csv/record[position() = (2 to 9)]
  !
  <record>
    <sex>{data(entry[3])}</sex>
  </record>
}
</csv>
于 2020-06-18T10:34:47.080 回答