如何通过分隔符拆分字符串,但如果它被转义则不行?例如,我有一个字符串:
1|2\|2|3\\|4\\\|4
定界符 is|
和转义定界符 is \|
。此外,我想忽略转义\\|
的反斜杠,所以 in|
仍然是一个分隔符。
所以使用上面的字符串,结果应该是:
[0] => 1
[1] => 2\|2
[2] => 3\\
[3] => 4\\\|4
如何通过分隔符拆分字符串,但如果它被转义则不行?例如,我有一个字符串:
1|2\|2|3\\|4\\\|4
定界符 is|
和转义定界符 is \|
。此外,我想忽略转义\\|
的反斜杠,所以 in|
仍然是一个分隔符。
所以使用上面的字符串,结果应该是:
[0] => 1
[1] => 2\|2
[2] => 3\\
[3] => 4\\\|4
使用黑魔法:
$array = preg_split('~\\\\.(*SKIP)(*FAIL)|\|~s', $string);
\\\\.
匹配后跟一个字符的反斜杠,(*SKIP)(*FAIL)
跳过它并\|
匹配您的分隔符。
而不是split(...)
,使用某种像词法标记器一样操作的“扫描”功能更直观。在 PHP 中,这将是preg_match_all
函数。你只是说你想匹配:
\
a or以外的东西|
\
后跟 a\
或|
以下演示:
$input = "1|2\\|2|3\\\\|4\\\\\\|4";
echo $input . "\n\n";
preg_match_all('/(?:\\\\.|[^\\\\|])+/', $input, $parts);
print_r($parts[0]);
将打印:
1|2\|2|3\\|4\\\|4
Array
(
[0] => 1
[1] => 2\|2
[2] => 3\\
[3] => 4\\\|4
)
最近我设计了一个解决方案:
$array = preg_split('~ ((?<!\\\\)|(?<=[^\\\\](\\\\\\\\)+)) \| ~x', $string);
但黑魔法解法还是快了三倍。
对于未来的读者,这是一个通用的解决方案。它基于 NikiC 的想法(*SKIP)(*FAIL)
:
function split_escaped($delimiter, $escaper, $text)
{
$d = preg_quote($delimiter, "~");
$e = preg_quote($escaper, "~");
$tokens = preg_split(
'~' . $e . '(' . $e . '|' . $d . ')(*SKIP)(*FAIL)|' . $d . '~',
$text
);
$escaperReplacement = str_replace(['\\', '$'], ['\\\\', '\\$'], $escaper);
$delimiterReplacement = str_replace(['\\', '$'], ['\\\\', '\\$'], $delimiter);
return preg_replace(
['~' . $e . $e . '~', '~' . $e . $d . '~'],
[$escaperReplacement, $delimiterReplacement],
$tokens
);
}
试一试:
// the base situation:
$text = "asdf\\,fds\\,ddf,\\\\,f\\,,dd";
$delimiter = ",";
$escaper = "\\";
print_r(split_escaped($delimiter, $escaper, $text));
// other signs:
$text = "dk!%fj%slak!%df!!jlskj%%dfl%isr%!%%jlf";
$delimiter = "%";
$escaper = "!";
print_r(split_escaped($delimiter, $escaper, $text));
// delimiter with multiple characters:
$text = "aksd()jflaksd())jflkas(('()j()fkl'()()as()d('')jf";
$delimiter = "()";
$escaper = "'";
print_r(split_escaped($delimiter, $escaper, $text));
// escaper is same as delimiter:
$text = "asfl''asjf'lkas'''jfkl''d'jsl";
$delimiter = "'";
$escaper = "'";
print_r(split_escaped($delimiter, $escaper, $text));
输出:
Array
(
[0] => asdf,fds,ddf
[1] => \
[2] => f,
[3] => dd
)
Array
(
[0] => dk%fj
[1] => slak%df!jlskj
[2] =>
[3] => dfl
[4] => isr
[5] => %
[6] => jlf
)
Array
(
[0] => aksd
[1] => jflaksd
[2] => )jfl'kas((()j
[3] => fkl()
[4] => as
[5] => d(')jf
)
Array
(
[0] => asfl'asjf
[1] => lkas'
[2] => jfkl'd
[3] => jsl
)
注意:存在理论水平问题:implode('::', ['a:', ':b'])
和implode('::', ['a', '', 'b'])
结果相同的字符串:'a::::b'
。内爆也是一个有趣的问题。
正则表达式非常缓慢。更好的方法是在拆分之前从字符串中删除转义字符,然后将它们放回:
$foo = 'a,b|,c,d||,e';
function splitEscaped($str, $delimiter,$escapeChar = '\\') {
//Just some temporary strings to use as markers that will not appear in the original string
$double = "\0\0\0_doub";
$escaped = "\0\0\0_esc";
$str = str_replace($escapeChar . $escapeChar, $double, $str);
$str = str_replace($escapeChar . $delimiter, $escaped, $str);
$split = explode($delimiter, $str);
foreach ($split as &$val) $val = str_replace([$double, $escaped], [$escapeChar, $delimiter], $val);
return $split;
}
print_r(splitEscaped($foo, ',', '|'));
在“,”上拆分,但如果用“|”转义则不会。它还支持双重转义,所以“||” 变成一个“|” 分裂发生后:
Array ( [0] => a [1] => b,c [2] => d| [3] => e )