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在socket.io-client中发送自定义标头时遇到问题。服务器端集成/代码一切正常,因为 iOS 代码运行良好。这是我在 iOS 中的代码:

let manager = SocketManager(socketURL: URL(string: "http://server_url_here/")!, 
                            config: [.log(true), 
                                     .compress, .extraHeaders(["Authorization": "Bearer \(Defaults[.authToken])"])])

现在我尝试了socket.io-client文档中提到的方法。这是我使用的代码:

final OkHttpClient httpClient = new OkHttpClient.Builder()
                    .addNetworkInterceptor(new CustomHeaderInterceptor())
                    .build();

//options    
final IO.Options options = new IO.Options();

options.webSocketFactory = httpClient;
options.callFactory = httpClient;

//manager
Manager manager = new Manager(URI.create(Constants.BASEURL));
socket = manager.socket("/event/0", options);

socket.connect();

但这在套接字错误处理程序中给出了错误:

io.socket.engineio.client.engineioexception xhr 发布错误

我也尝试使用下面的代码但不工作:

socket.io().on(Manager.EVENT_TRANSPORT, new Emitter.Listener() {
    @Override
    public void call(Object... args) {
        Transport transport = (Transport) args[0];
        // Adding headers when EVENT_REQUEST_HEADERS is called
        transport.on(Transport.EVENT_REQUEST_HEADERS, new Emitter.Listener() {
            @Override
            public void call(Object... args) {
                Map<String, List<String>> mHeaders = (Map<String, List<String>>)args[0];
                mHeaders.put("Authorization", Arrays.asList(auth_token_with_bearer));        
            }
        });
        transport.on(Transport.EVENT_RESPONSE_HEADERS, new Emitter.Listener() {
            @Override
            public void call(Object... args) {
                @SuppressWarnings("unchecked")
                Map<String, List<String>> headers = (Map<String, List<String>>)args[0];
                // access response headers
                String auth = headers.get("Authorization").get(0);


            }
        });
    }
});

我阅读了许多与此问题相关的主题,但没有一个对我有用。请让我知道我现在哪里错了。

4

1 回答 1

-1
OkHttpClient.Builder httpClient = new OkHttpClient.Builder();

httpClient.addInterceptor(new Interceptor() {

@Override
public Response intercept(Interceptor.Chain chain) throws IOException {
    Request original = chain.request();

    Request request = original.newBuilder()
        .header("User-Agent", "Your-App-Name")
        .header("Accept", "application/json")
        .header("your_header_key", "value")
        .method(original.method(), original.body())
        .build();

    return chain.proceed(request);
}
}

 OkHttpClient client = httpClient.build();
于 2020-06-16T15:57:42.327 回答