swift - 初始化嵌入式结构的正确方法是什么？

Question

场景：我在 Struct 中有一个用于保存 JSON 数据的结构。
目标：我希望能够通过 init() 填充子结构以进行一些单元测试工作。

struct PortEligibility: Codable {
    var myVar = ""
    struct PortMobileNumber: Codable {
        let one: String?
        let two: String?
        let three: String?
    }
}

我一直在玩弄这个，但我迷路了：

我不想使用解码器。
补救？

Answer 1

如果 struct 基本定义没有任何自定义 init 方法，您将获得成员初始值设定项。

let number = PortEligibility.PortMobileNumber(one: "one", two: "two", three: "three")

此外，您可以提供默认值nilor ""（空字符串）或指定默认值nil与结构的定义一起使用，并使空初始值设定项可用于结构，如下所示：

// Sample 1
let number = PortEligibility.PortMobileNumber(one: nil, two: nil, three: nil)
// or Sample 2
struct PortEligibility: Codable {
    var myVar = ""
    struct PortMobileNumber: Codable {
        var one: String? = nil
        var two: String? = nil
        var three: String? = nil
    }
}
let number = PortEligibility.PortMobileNumber()

Answer 2

我相信我有解决方案：

let number = PortEligibility.PortMobileNumber(one: "One", two: "Two", three: "Three")

struct PortEligibility: Codable {
    var myVar = ""
    struct PortMobileNumber: Codable {
        var one: String? = nil
        var two: String? = nil
        var three: String? = nil
        init(one: String?, two: String?, three: String?) {
            self.one = one
            self.two = two
            self.three = three
        }
    }

    public func getNumber() -> PortMobileNumber {
        let portMobileNuber = PortMobileNumber(one: "Hello",
                                               two: "Every",
                                               three: "Body")
        return portMobileNuber
    }
}

var portEligibility = PortEligibility()
portEligibility.myVar = "Hello World!"

print(portEligibility)
print(portEligibility.getNumber())

print(number)

输出：

PortEligibility(myVar: "Hello World!") PortMobileNumber(一: Optional("Hello"), 二: Optional("Every"), 三: Optional("Body")) PortMobileNumber(一: Optional("One"),二：可选（“二”），三：可选（“三”））