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以下代码用于加密纯文本，我在下面的示例代码中使用IAIK Twofish加密/解密代码在 java 中使用 128 位密钥可以正常工作，但是当我使用 192 和 156 位密钥尝试它时，它给出了一个例外 java.security.InvalidKeyException: Key must be 128, 192, or 256 bit long!-

private static void doCrypto(int cipherMode, String key, File inputFile, File outputFile) throws CryptoException {
        try {
            SecretKey secretKey = new SecretKeySpec(key.getBytes(), ALGORITHM);
            Cipher cipher = Cipher.getInstance(TRANSFORMATION, "IAIK");
            cipher.init(cipherMode, secretKey); 
            FileInputStream inputStream = new FileInputStream(inputFile);
            byte[] inputBytes = new byte[(int) inputFile.length()];
            inputStream.read(inputBytes);
            byte[] outputBytes = cipher.doFinal(inputBytes);
            FileOutputStream outputStream = new FileOutputStream(outputFile);
            outputStream.write(outputBytes);
            inputStream.close();
            outputStream.close();
        } catch (NoSuchPaddingException | NoSuchAlgorithmException | InvalidKeyException | BadPaddingException
                | IllegalBlockSizeException | IOException ex) {
            throw new CryptoException("Error encrypting/decrypting file", ex);
        } catch (NoSuchProviderException e) {
            // TODO Auto-generated catch block
            e.printStackTrace();
        }
    }

对于上述方法，当我提供 128 位密钥时，它可以正常工作，如下所示，

    KeyGenerator keyGen = KeyGenerator.getInstance("Twofish", "IAIK");
    keyGen.init(192);
    txtSecretKey.setText(iaik.utils.Util.toString(key.getEncoded()));
    SekertKey key = key.generateKey();
    encrypt(txtSecretKey.getText(), inputFile, encryptedFile);
Caused by: java.security.InvalidKeyException: Key must be 128, 192, or 256 bit long!
    at iaik.security.cipher.N.a(Unknown Source)
    at iaik.security.cipher.i.a(Unknown Source)
    at iaik.security.cipher.a.engineInit(Unknown Source)
    at javax.crypto.Cipher.init(Cipher.java:1249)
    at javax.crypto.Cipher.init(Cipher.java:1189)
    at com.opensourse.crypto.twofish.CryptoUtils.doCrypto(CryptoUtils.java:38)
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3 回答 3

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确保您从此处获得“java 加密扩展 (jce) 无限强度管辖策略文件 8” 。有关说明，请参阅此。

于 2020-06-10T07:43:22.583 回答
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仔细检查一些答案总是好的，因为错误“128bit aes key is working, 192/256 keys not”是有限加密策略的症状。请运行这个小程序并在控制台上向我们展示结果（“false”表示无限制的加密策略......）

import javax.crypto.Cipher;
import java.security.NoSuchAlgorithmException;
public class Main {
    public static void main(String[] args) {
        System.out.println("\nTest with Java version: " + Runtime.version());
        System.out.println("Java restricted cryptography: " + restrictedCryptography());
    }
    /**
     * Determines if cryptography restrictions apply.
     * Restrictions apply if the value of {@link Cipher#getMaxAllowedKeyLength(String)} returns a value smaller than {@link Integer#MAX_VALUE} if there are any restrictions according to the JavaDoc of the method.
     * This method is used with the transform <code>"AES/CBC/PKCS5Padding"</code> as this is an often used algorithm that is <a href="https://docs.oracle.com/javase/8/docs/technotes/guides/security/StandardNames.html#impl">an implementation requirement for Java SE</a>.
     *
     * @return <code>true</code> if restrictions apply, <code>false</code> otherwise
     *
     * code by Maarten Bodewes, https://stackoverflow.com/questions/7953567/checking-if-unlimited-cryptography-is-available#
     */
    public static boolean restrictedCryptography() {
        try {
            return Cipher.getMaxAllowedKeyLength("AES/CBC/PKCS5Padding") < Integer.MAX_VALUE;
        } catch (final NoSuchAlgorithmException e) {
            throw new IllegalStateException("The transform \"AES/CBC/PKCS5Padding\" is not available (the availability of this algorithm is mandatory for Java SE implementations)", e);
        }
    }
}
于 2020-06-10T18:01:41.613 回答
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在您的主要方法中，您将 SecretKey 转换为显示在（GUI）文本字段中的字符串。打印出密钥的内容如下所示：

key in hex: 7b44a1f09136a248a40c8043fa02fbcf
textfield : 7B:44:A1:F0:91:36:A2:48:A4:0C:80:43:FA:02:FB:CF

将文本字段中的此字符串转换回 byte[] 以使用“.getBytes”重新生成 secretKey 将失败，因为冒号字符也将被解码：

SecretKey secretKey = new SecretKeySpec(key.getBytes(), ALGORITHM)

IAIK-Util-class 提供了一个“.toByteArray”方法，它简单地忽略除 '0-9' 和 'af' 之外的其他字符，请参阅http://javadoc.iaik.tugraz.at/iaik_jce/current/iaik中的文档/utils/Util.html：

将具有十六进制值的给定字符串转换为字节数组。例如 "001122" 变成 {0, 0x11, 0x22}。'0'-'9'、'a'-'z' 和 'A'-'Z' 范围之外的所有字符或直接忽略。

只需更改 doCrypto-method 中的行，一切正常：

SecretKey secretKey = new SecretKeySpec(iaik.utils.Util.toByteArray(key), ALGORITHM);
于 2020-06-11T11:10:34.877 回答