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我有这样的数据假人

CREATE TABLE A  ( users_id INT);
INSERT INTO A  VALUES (1), (2), (3), (4);
CREATE TABLE B (users_id INT);
INSERT INTO B VALUES (2), (3), (4), (5);
CREATE TABLE C (users_id INT);
INSERT INTO C VALUES (3), (4), (5), (6);
CREATE TABLE D (users_id INT);
INSERT INTO D VALUES (4), (5), (6), (7);

我想选择表 D 和 B 上存在但不存在于表 A 上的 users_id

我试过这个查询

SELECT DISTINCT b1.users_Id FROM b b1
      WHERE EXISTS (SELECT d1.users_Id FROM D d1
                WHERE b1.users_id = d1.users_id)
       AND NO EXISTS (SELECT a1.users_id from A a1
                      WHERE a1.users_id = d1.users_id
                      and a1.users_id = b1.users_id
                      and b1.users_id = d1.users_id);

但是mysql说

You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near 'EXISTS (SELECT a1.users_id from A a1 WHERE a1.users_id = d' at line 4

这是小提琴http://sqlfiddle.com/#!9/2bff8e/10

4

1 回答 1

1

相同查询的替代形式：

SELECT DISTINCT b.users_Id
FROM b
JOIN d
  ON b.users_id = d.users_id
LEFT JOIN a
  ON b.users_id = a.users_id
WHERE a.users_id IS NULL
于 2020-06-09T02:58:45.363 回答