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这是一个非常简单且可能很愚蠢的问题,但我忘记了如何使用QList QVariant::toList () const
QVariant s = this->page()->mainFrame()->evaluateJavaScript (QString ("Open(%1,%2)").arg (point.x()).arg (point.y())); List<QVariant> x; x = s.toList ();
当然这是错误的,正确的出路是什么?:脸红:
你所做的几乎是正确的:
QList<QVariant> x = s.toList();
(注意使用QList代替List。)
QList
List
你所做的是对的。可能您可以在转换之前检查变体是否包含列表。例如:
QVariant variant = list; if(variant.canConvert(QVariant::List)) { QList<QVariant> list_1 = variant.toList(); }