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我正在尝试使用 predict() 函数使用 X_trainT 和 X_testT 预测测试和训练数据的输出。我收到以下列出的错误 -

yPredTrain = predict(X_trainT, parameters)   
yPredTest = predict(X_testT, parameters)    # This function is throwing the error

预测功能

def predict(X, parameters):
  W = parameters["W"]
  b = parameters["b"]
  W = W.reshape(X.shape[0], 1)
  #Z = np.dot(W.T,X) + b
  Z = np.dot(W.T,X) + b
  Y = np.array([1 if y > 0.5 else 0 for y in sigmoid(Z[0])]).reshape(1,len(Z[0]))
  #Y = np.array([1 if y > 0.5 else 0 for y in Z[0]]).reshape(1,len(Z[0]))
  return Y

错误

ValueError                                Traceback (most recent call last)
<ipython-input-20-a5c2d40ef32d> in <module>()
      1 yPredTrain = predict(X_trainT, parameters)   
----> 2 yPredTest = predict(X_testT, parameters)    

<ipython-input-9-dfb2f70a0c07> in predict(X, parameters)
      4   W = W.reshape(X.shape[0], 1)
      5   #Z = np.dot(W.T,X) + b
----> 6   Z = np.dot(W.T,X) + b
      7   Y = np.array([1 if y > 0.5 else 0 for y in sigmoid(Z[0])]).reshape(1,len(Z[0]))
      8   #Y = np.array([1 if y > 0.5 else 0 for y in Z[0]]).reshape(1,len(Z[0]))

ValueError: operands could not be broadcast together with shapes (1,143) (426,) ```
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