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我编写了下面的代码来使用 Python 中的 2 个单独的线程打印偶数和奇数，但是这段代码不起作用（程序没有显示任何输出，并且期望按顺序打印 0-10 的数字）。任何帮助进行调试将不胜感激。下面是代码：

from threading import Thread
from threading import Event


even_available = Event()
odd_available = Event()

def print_even():
    global limit
    global exit_prog
    global number

    while not exit_prog and number <= limit:
        print(number)
        number = number + 1
        even_available.clear()

        odd_available.set()

def print_odd():
    global limit
    global exit_prog
    global number

    odd_available.wait()
    while not exit_prog and number <= limit:
        print(number)
        number = number+1
        odd_available.clear()
        even_available.set()

if __name__ == "__main__":

    limit = 10
    exit_prog = False
    number = 0

    t1 = Thread(target=print_even)
    t2 = Thread(target=print_odd)

    even_available.set()

    t1.start()
    t2.start()

    t1.join()
    t2.join()
4

2 回答 2

0

使用多处理使代码更简洁。如果不需要，您还希望避免使用全局变量。

from multiprocessing import Process

def print_even(limit, exit_prog, number):
    while not exit_prog and number <= limit:
        if(number % 2 == 0):
            print(number)
        number = number + 1

def print_odd(limit, exit_prog, number):
    while not exit_prog and number <= limit:
        if(number % 2 == 1):
            print(number)
        number = number + 1

if __name__ == "__main__":

    limit = 10
    exit_prog = False
    number = 0

    t1 = Process(target=print_even, args=(limit, exit_prog, number))
    t1.start()
    t2 = Process(target=print_odd, args=(limit, exit_prog, number))
    t2.start()

    t1.join()
    t2.join()
于 2020-05-24T12:48:21.267 回答
0

您只是忘记了wait()for even_available/odd_available在 while 循环内：

from threading import Thread
from threading import Event

even_available = Event()
odd_available = Event()

def print_even():
    global limit
    global exit_prog
    global number

    while not exit_prog and number < limit:
        even_available.wait()
        print('E', number)
        number = number + 1
        even_available.clear()
        odd_available.set()

def print_odd():
    global limit
    global exit_prog
    global number

    while not exit_prog and number < limit:
        odd_available.wait()
        print('O', number)
        number = number + 1
        odd_available.clear()
        even_available.set()

if __name__ == "__main__":

    limit = 10
    exit_prog = False
    number = 0

    t1 = Thread(target=print_even)
    t2 = Thread(target=print_odd)

    even_available.set()

    t1.start()
    t2.start()

    t1.join()
    t2.join()

印刷：

E 0
O 1
E 2
O 3
E 4
O 5
E 6
O 7
E 8
O 9
E 10
于 2020-05-24T12:49:07.400 回答