1

我目前有一个这种格式的分隔文件（2 列选项卡“\t”分隔）和“;” 分隔列中的所有元素）。

    User\tDate

    Alice Cooper;John Smith\t07/11/2019

    Alice Cooper\t23/11/2018

    Alice Cooper\t21/11/2018

    Alice Cooper\t26/11/2018

    Alice Cooper\t26/11/2018

    Alice Cooper;John Smith\t09/12/2018

    Alice Cooper;John Smith\t09/12/2018

    Alice Cooper;John Smith\t04/12/2018

    Alice Cooper\t07/12/2018

    Alice Cooper\t07/12/2018

我想对优化宏（最好是 javascript）有任何想法，以创建以下 OUTPUT 文件：

    User\tEarliest\tLatest\tDates_with_Most_Occurences\tMost_Occurence_Number

    Alice Cooper\t21/11/2018\t07/11/2019\t26/11/2018;07/12/2018\t2

    John Smith\t04/12/2018\t07/11/2019\t09/12/2018\t1

所以中间步骤（我目前正在手动执行，但想转入宏）：

第 1 步：分离列 1 中的名称元素

（给出这样的东西）：

    User\tDate

    Alice Cooper\t07/11/2019

    John Smith\t07/11/2019

    Alice Cooper\t23/11/2018

    Alice Cooper\t21/11/2018

    Alice Cooper\t26/11/2018

    Alice Cooper\t26/11/2018

    Alice Cooper\t09/12/2018

    John Smith\t09/12/2018

    Alice Cooper\t09/12/2018

    John Smith\t09/12/2018

    Alice Cooper\t04/12/2018

    John Smith\t04/12/2018

    Alice Cooper\t07/12/2018

    Alice Cooper\t07/12/2018

第 2 步：对 Col1 AZ 和 Col 2 最旧到最新进行排序。现在基于 Column 1 组合 Column 2 元素（给出类似的内容）：

    User\tDate


    Alice Cooper\t21/11/2018;23/11/2018;26/11/2018;26/11/2018;04/12/2018;07/12/2018;07/12/2018;09/12/2018;09/12/2018;07/11/2019;

    John Smith\t04/12/2018;09/12/2018;09/12/2018;07/11/2019;

第 3 步：现在在 Col2 中为每一行获取日期信息并创建这 4 个新列：EarliestDate、LatestDate、Dates_with_Most_Occurences、Most_Occurence_Number（给出类似的内容）：

    User\tDate

    Alice Cooper\t21/11/2018;23/11/2018;26/11/2018;26/11/2018;04/12/2018;07/12/2018;07/12/2018;09/12/2018;09/12/2018;07/11/2019;

    John Smith\t04/12/2018;09/12/2018;09/12/2018;07/11/2019;

第 4 步：删除 Col2（日期）：给出最终输出：

    User\tEarliestDate\tLatestDate\tDates_with_Most_Occurences\tMost_Occurence_Number

    Alice Cooper\t21/11/2018\t07/11/2019\t26/11/2018;07/12/2018\t2

    John Smith\t04/12/2018\t07/11/2019\t09/12/2018\t1

我只需要宏来创建最终输出，中间（上面的步骤 1、2、3）只是显示了我正在尝试做的事情的逻辑。真正的源文件将有数千行，所以如果这可以被 EmEditor 以任何方式优化，那就太棒了。

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1 回答 1

2

假设您的数据文件不包含空行，这里是脚本。

document.ConvertCsv(2); // This assumes your Tab format is the second one on the CSV/Sort bar

function parseDate(s) {
    var split = s.split('/');
    return new Date(split[2], split[1] - 1, split[0]);
}

var data = [];

// Read the file
var numberOfLines = document.GetLines();
if (numberOfLines >= 2 && document.GetLine(2) === '') {
    numberOfLines = 1; // CSV document only has header without data
}

for (var line = 1; line < numberOfLines; line++) {
    var rowData = [
        document.GetCell(line + 1, 1, eeCellIncludeNone),
        parseDate(document.GetCell(line + 1, 2, eeCellIncludeNone)),
    ];
    data.push(rowData);
}

// Separate combined users
var separated = [];
for (var row = 0; row < data.length; row++) {
    var split = data[row][0].split(';');
    for (var i = 0; i < split.length; i++) {
        separated.push([split[i], data[row][1]]);
    }
}

// Group by user
// {[key: string]: {data: [[]], earliest: Date, latest: Date, mostOccurrence: Date, occurrence: number}}
var users = {};

for (var row = 0; row < separated.length; row++) {
    if (!(separated[row][0] in users)) {
        users[separated[row][0]] = {data: []};
    }

    users[separated[row][0]].data.push(separated[row]);
}

// At this point, we have parsed the file into useful data.
// alert(JSON.stringify(users, null, '  ')); // To check

// Data analysis
for (var userKey in users) {
    var sorted = users[userKey].data.sort(function(a, b) {
        return a[1].getTime() - b[1].getTime();
    });
    users[userKey].earliest = sorted[0][1];
    users[userKey].latest = sorted[sorted.length - 1][1];

    // Count dates
    var dates = {}; // {[key: number]: number}
    for (var i = 0; i < sorted.length; ++i) {
        if (!(sorted[i][1].getTime() in dates)) {
            dates[sorted[i][1].getTime()] = 0;
        }

        dates[sorted[i][1].getTime()] += 1;
    }

    var mostOccurrence = {date: [], occurrence: -1};
    for (var k in dates) {
        if (dates[k] > mostOccurrence.occurrence) {
            mostOccurrence = {date: [k], occurrence: dates[k]}
        } else if (dates[k] === mostOccurrence.occurrence) {
            mostOccurrence.date.push(k);
        }
    }

    users[userKey].mostOccurrence = [];
    for (var i = 0; i < mostOccurrence.date.length; i++) {
        var date = new Date();
        date.setTime(mostOccurrence.date[i]);
        users[userKey].mostOccurrence.push(date);
    }
    users[userKey].occurrence = mostOccurrence.occurrence;
}

// Format the numbers and output to document
editor.NewFile();
document.selection.Text = 'User\tEarliestDate\tLatestDate\tDates_with_Most_Occurences\tMost_Occurence_Number';
for (var _ in users) {
    document.selection.Text += '\r\n';
}
document.ConvertCsv(2);

function formatDate(d) {
    return d.getDate() + '/' + (d.getMonth() + 1) + '/' + d.getFullYear();
}

var line = 2;
for (var userKey in users) {
    document.SetCell(line, 1, userKey, eeAutoQuote);
    document.SetCell(line, 2, formatDate(users[userKey].earliest), eeAutoQuote);
    document.SetCell(line, 3, formatDate(users[userKey].latest), eeAutoQuote);
    var mostOccurrenceStr = '';
    for (var i = 0; i < users[userKey].mostOccurrence.length; i++) {
        mostOccurrenceStr += formatDate(users[userKey].mostOccurrence[i]) + ';';
    }
    document.SetCell(line, 4, mostOccurrenceStr.substring(0, mostOccurrenceStr.length - 1), eeAutoQuote);
    document.SetCell(line, 5, users[userKey].occurrence, eeAutoQuote);
    line++;
}

希望它有效，但如果没有，请告诉我。

于 2020-05-21T04:23:29.100 回答