88

我想模拟一个长按按钮,我该怎么做?我认为需要一个计时器。我明白UILongPressGestureRecognizer了,但我怎样才能使用这种类型?

4

9 回答 9

161

您可以从创建UILongPressGestureRecognizer实例并将其附加到按钮开始。

UILongPressGestureRecognizer *longPress = [[UILongPressGestureRecognizer alloc] initWithTarget:self action:@selector(longPress:)];
[self.button addGestureRecognizer:longPress];
[longPress release];

然后实现处理手势的方法

- (void)longPress:(UILongPressGestureRecognizer*)gesture {
    if ( gesture.state == UIGestureRecognizerStateEnded ) {
         NSLog(@"Long Press");
    }
}

现在这将是基本方法。您还可以设置压力机的最短持续时间以及可以容忍的错误量。另请注意,如果您在识别手势后会调用该方法几次,因此如果您想在结束时执行某些操作,则必须检查其状态并进行处理。

于 2011-05-30T18:27:38.813 回答
28

作为公认答案的替代方案,这可以在 Xcode 中使用 Interface Builder 轻松完成。

只需从对象库中拖动一个长按手势识别器并将其放在您想要长按操作的按钮顶部。

接下来,将刚刚添加的Long Press Gesture Recognizer中的 Action 连接到您的视图控制器,选择 sender 类型为UILongPressGestureRecognizer。在IBAction使用这个的代码中,这与接受的答案中建议的代码非常相似:

Objective-C 中

if ( sender.state == UIGestureRecognizerStateEnded ) {
     // Do your stuff here
}

或者在Swift中:

if sender.state == .Ended {
    // Do your stuff here
}

但我不得不承认,在尝试之后,我更喜欢@shengbinmeng 提出的建议作为对已接受答案的评论,即使用:

Objective-C 中

if ( sender.state == UIGestureRecognizerStateBegan ) {
     // Do your stuff here
}

或者在Swift中:

if sender.state == .Began {
    // Do your stuff here
}

不同之处在于Ended,您可以在抬起手指时看到长按的效果。使用Began,您可以在系统捕捉到长按后立即看到长按的效果,甚至在您将手指从屏幕上移开之前。

于 2014-11-05T12:18:03.647 回答
19

已接受答案的 Swift 版本

我对使用UIGestureRecognizerState.Began而不是进行了额外的修改,.Ended因为这可能是大多数用户自然期望的。不过,尝试它们并亲自看看。

import UIKit

class ViewController: UIViewController {

    @IBOutlet weak var button: UIButton!
    
    override func viewDidLoad() {
        super.viewDidLoad()
        
        // add gesture recognizer
        let longPress = UILongPressGestureRecognizer(target: self, action: #selector(longPress(_:)))
        self.button.addGestureRecognizer(longPress)
        
    }

    func longPress(gesture: UILongPressGestureRecognizer) {
        if gesture.state == UIGestureRecognizerState.began {
            print("Long Press")
        }
    }
    
    @IBAction func normalButtonTap(sender: UIButton) {
        print("Button tapped")
    }
}
于 2015-12-04T07:41:47.123 回答
10

试试这个:

添加按钮viewDidLoad:如下

-(void)viewDidLoad {
    UIButton *btn = [UIButton buttonWithType:UIButtonTypeRoundedRect];
    [btn setTag:1]; //you can set any integer value as tag number
    btn.title = @"Press Me";
    [btn setFrame:CGRectMake(50.0, 50.0, 60.0, 60.0)];

    // now create a long press gesture
    UILongPressGestureRecognizer *longPress = [[UILongPressGestureRecognizer alloc]initWithTarget:self action:@selector(longPressTap:)];
    [btn addGestureRecognizer:longPress];
}

现在像这样调用手势方法

-(void)longPressTap:(id)sender {
     UIGestureRecognizer *recognizer = (UIGestureRecognizer*) sender
    // Recogniser have all property of button on which you have clicked
    // Now you can compare button's tag with recogniser's view.tag  
    // View frame for getting the info on which button the click event happened 
    // Then compare tag like this
    if(recognizer.view.tag == 1) { 
       // Put your button's click code here
    }

    // And you can also compare the frame of your button with recogniser's view
    CGRect btnRect = CGRectMake(50.0, 50.0, 60.0, 60.0);
    if(recogniser.view.frame == btnRect) {
       //put your button's click code here
    }

   // Remember frame comparing is alternative method you don't need  to write frame comparing code if you are matching the tag number of button 
}
于 2012-05-18T14:59:24.313 回答
4

我想你需要我的解决方案。

你应该有这个代码单按

- (IBAction)buttonDidPress:(id)sender {
    NSLog("buttonDidPress");
}

首先,在按钮上添加长按手势

- (void)viewWillAppear:(BOOL)animated
{
    UILongPressGestureRecognizer *longPress = [[UILongPressGestureRecognizer alloc] initWithTarget:self action:@selector(buttonDidLongPress:)];
    [self.button addGestureRecognizer:longPress];
}

如果识别出长按手势,则重复调用单按事件。

- (void)buttonDidLongPress:(UILongPressGestureRecognizer*)gesture
{
    switch (gesture.state) {
        case UIGestureRecognizerStateBegan:
        {
            self.timer = [NSTimer timerWithTimeInterval:0.1 target:self selector:@selector(buttonDidPress:) userInfo:nil repeats:YES];

            NSRunLoop * theRunLoop = [NSRunLoop currentRunLoop];
            [theRunLoop addTimer:self.timer forMode:NSDefaultRunLoopMode];
        }
            break;
        case UIGestureRecognizerStateEnded:
        {
            [self.timer invalidate];
            self.timer = nil;
        }
            break;
        default:
            break;
    }
}
于 2015-05-24T08:22:26.440 回答
3

对于 Swift 4,需要更改“func longPress”以使其工作:

import UIKit

class ViewController: UIViewController {

    @IBOutlet weak var button: UIButton!

    override func viewDidLoad() {
        super.viewDidLoad()

        // add guesture recognizer
        let longPress = UILongPressGestureRecognizer(target: self, action: #selector(longPress(_:)))
        self.button.addGestureRecognizer(longPress)

    }

   @objc func longPress(_ guesture: UILongPressGestureRecognizer) {
        if guesture.state == UIGestureRecognizerState.began {
            print("Long Press")
        }
    }

    @IBAction func normalButtonTap(sender: UIButton) {
        print("Button tapped")
    }
}
于 2018-02-13T11:58:14.590 回答
1

没有手势的单行回答:

[btn addTarget:self action:@selector(handleTouch:) forControlEvents:UIControlEventTouchDown | UIControlEventTouchUpInside | UIControlEventTouchUpOutside];

详细信息: 这会在三个事件上触发您的目标: 1- 一旦手指按下按钮:UIControlEventTouchDown。这捕获了长按开始。2 & 3- 当用户抬起手指时:UIControlEventTouchUpOutside& UIControlEventTouchUpInside。这将捕获用户按下的结束。

注意:如果您不关心手势识别器提供的额外信息(例如触摸位置等),这很有效

如果需要,您可以添加更多中间事件在这里查看它们https://developer.apple.com/documentation/uikit/uicontrolevents?language=objc

在 Storyboard 中: 将您的按钮连接到 3 个事件,而不仅仅是 Storyboard 选择的默认事件(Touch Up Inside)。

故事板中的 3 个事件

于 2020-04-20T18:43:19.877 回答
0

我的应用程序有一个子类 UIButton,所以我退出了我的实现。您可以将其添加到您的子类中,也可以像 UIButton 类别一样轻松地重新编码。

我的目标是将长按添加到我的按钮上,而不会使我的视图控制器与所有代码混淆。我决定在手势识别器状态开始时调用该动作。

有一个警告出现,我从来没有费心去解决。说这是可能的泄漏,以为我已经测试了代码并且它没有泄漏。

@interface MYLongButton ()
@property (nonatomic, strong) UILongPressGestureRecognizer *gestureRecognizer;
@property (nonatomic, strong) id gestureRecognizerTarget;
@property (nonatomic, assign) SEL gestureRecognizerSelector;
@end

@implementation MYLongButton

- (void)addLongPressTarget:(CGFloat)interval target:(id)target action:(SEL)selector
{
    _gestureRecognizerTarget = target;
    _gestureRecognizerSelector = selector;
    _gestureRecognizer = [[UILongPressGestureRecognizer alloc]initWithTarget:self action:@selector(handleLongPressGestureRecognizer:)];
    _gestureRecognizer.minimumPressDuration = interval;

    [self addGestureRecognizer:_gestureRecognizer];
}

- (void)handleLongPressGestureRecognizer:(UIGestureRecognizer *)gestureRecognizer
{
    if (gestureRecognizer.state == UIGestureRecognizerStateBegan) {
        NSAssert([_gestureRecognizerTarget respondsToSelector:_gestureRecognizerSelector], @"target does not respond to selector");

        self.highlighted = NO;

        // warning on possible leak -- can anybody fix it?
        [_gestureRecognizerTarget performSelector:_gestureRecognizerSelector withObject:self];
    }
}

要分配操作,请将此行添加到您的 viewDidLoad 方法。

[_myLongButton addLongPressTarget:0.75 target:self selector:@selector(longPressAction:)];

动作应该像所有 IBAction 一样定义(没有 IBAction)。

- (void)longPressAction:(id)sender {
    // sender is the button
}
于 2015-09-22T13:53:02.650 回答
0

没有工作,因此我尝试编写长按代码IBAction或按钮单击storyboardController不是写入viewDidLoad

- (IBAction)btnClick:(id)sender {

    tag = (int)((UIButton *)sender).tag;

// Long press here instead of in viewDidLoad

    UILongPressGestureRecognizer *longPress = [[UILongPressGestureRecognizer alloc] initWithTarget:self action:@selector(longPress:)];
    longPress.cancelsTouchesInView = NO;
    [sender addGestureRecognizer:longPress];

}
于 2017-12-08T10:20:52.087 回答