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试试这个解决方案:
listwords = [['people','suffering','acute'], ['Covid-19','Corona','like'], ['people','must','collectively']]
listsent = ['The number of people suffering acute hunger could almost double.',
'Lockdowns and global economic recession have',
'one more shock – like Covid-19 – to push them over the edge',
'people must collectively act now to mitigate the impact']
# interate through each sentence
for sentence in listsent:
# iterate through each group of words
for words in listwords:
# check to see if each word group is in the current sentence
if all(word in sentence for word in words):
print(sentence)
我评论了这些台词,让您了解发生了什么
代码的第一部分遍历列表中的每个句子
for sentence in listsent:
然后我们需要遍历单词列表中的单词组
for words in listwords
这就是事情变得有趣的地方。由于您有嵌套列表,我们需要检查以确保在句子中找到所有三个单词
if all(word in sentence for word in words):
最后,您可以打印出包含所有单词的每个句子
print(sentence)
你也可以把它放在一个函数中,并将找到的句子作为一个新列表返回
listwords = [['people','suffering','acute'], ['Covid-19','Corona','like'], ['people','must','collectively']]
listsent = ['The number of people suffering acute hunger could almost double.',
'Lockdowns and global economic recession have',
'one more shock – like Covid-19 – to push them over the edge',
'people must collectively act now to mitigate the impact']
def check_words(listwords, listsent):
listsent_new = []
# interate through each sentence
for sentence in listsent:
# iterate through each group of words
for words in listwords:
# check to see if each word group is in the current sentence
if all(word in sentence for word in words):
listsent_new.append(sentence)
return listsent_new
if __name__ == '__main__':
print(check_words(listwords, listsent))