python - 根据推文的数据框行在列中输出 vader 情绪分数

Question

我有一个包含多行推文的数据框，我想使用 vader 情绪分析根据每行的内容创建 4 列分数“正”、“负”、“中性”和“复合”。

我查找了不同的帖子，但我无法弄清楚我的确切情况。先感谢您！

Answer 1

实际上，我找到了一个简单的解决方案，可以通过列表推导来解决遇到相同问题的任何人：

analyzer = SentimentIntensityAnalyzer()
df['compound'] = [analyzer.polarity_scores(x)['compound'] for x in df['tweet']]
df['neg'] = [analyzer.polarity_scores(x)['neg'] for x in df['tweet']]
df['neu'] = [analyzer.polarity_scores(x)['neu'] for x in df['tweet']]
df['pos'] = [analyzer.polarity_scores(x)['pos'] for x in df['tweet']]

Answer 2

像这样的东西应该工作：

analyzer = SentimentIntensityAnalyzer()
df['rating'] = df['tweets'].apply(analyzer.polarity_scores)
pd.concat([df.drop(['rating'], axis=1), df['rating'].apply(pd.Series)], axis=1)

Answer 3

我在 python 3 中使用 Vader 进行情感分析完成了相同类型的工作。看看你可能会找到一种方法来执行你需要的东西。

from vaderSentiment.vaderSentiment import SentimentIntensityAnalyzer
import time
analyzer = SentimentIntensityAnalyzer()

pos_count = 0
pos_correct = 0

with open("D:/Corona_Vac/pythonprogramnet/Positive BOW.txt","r") as f:
    for line in f.read().split('\n'):
        vs = analyzer.polarity_scores(line)
        if not vs['neg'] > 0.1:
            if vs['pos']-vs['neg'] > 0:
                pos_correct += 1
            pos_count +=1


neg_count = 0
neg_correct = 0

with open("D:/Corona_Vac/pythonprogramnet/Positive BOW.txt","r") as f:
    for line in f.read().split('\n'):
        vs = analyzer.polarity_scores(line)
        if not vs['pos'] > 0.1:
            if vs['pos']-vs['neg'] <= 0:
                neg_correct += 1
            neg_count +=1

print("Positive accuracy = {}% via {} samples".format(pos_correct/pos_count*100.0, pos_count))
print("Negative accuracy = {}% via {} samples".format(neg_correct/neg_count*100.0, neg_count))

希望你能修复。谢谢