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我正在寻找python线以将失败的卡传递到第二天。
假设我们正在研究一副 3 张牌。我失败了2张牌,只成功了1张。当我想在第一次复习后重新研究失败的卡片时,我会停止修改,以便我可以启动我的插件直接将失败的卡片传递为成功完成我今天的套牌。然后明天我会看到我前一天失败的两张牌。
我得到了解决方案!这里是:
import time card = mw.col.getCard(1588339124244) print(card) card.timerStarted = time.time() # Start a timer otherwise it won't work mw.col.sched.answerCard(card, 2)