17

请问有人可以帮我解决吗?

可以这样做

   Tika tika = new Tika();
   tika.setMaxStringLength(10*1024*1024);

但是如果你不直接使用 Tika,像这样:

ContentHandler textHandler = new BodyContentHandler();
Metadata metadata = new Metadata();
Parser parser = new AutoDetectParser();

ParseContext ps = new ParseContext();
for (InputStream is : getInputStreams()) {
    parser.parse(is, textHandler, metadata, ps);
    is.close();
    System.out.println("Title: " + metadata.get("title"));
    System.out.println("Author: " + metadata.get("Author"));
}

无法设置它,因为您不与WriteOutContentHandler. 顺便说一句,它-1默认设置为没有限制。但由此产生的限制是 100000 个字符。

/**
 * The maximum number of characters to write to the character stream.
 * Set to -1 for no limit.
 */
private final int writeLimit;

/**
 * Number of characters written so far.
 */
private int writeCount = 0;

private WriteOutContentHandler(Writer writer, int writeLimit) {
    this.writer = writer;
    this.writeLimit = writeLimit;
}

/**
 * Creates a content handler that writes character events to
 * the given writer.
 *
 * @param writer writer
 */
public WriteOutContentHandler(Writer writer) {
    this(writer, -1);
}
4

1 回答 1

38

您一定忽略了内容处理程序具有带有 writelimit 的构造函数。

ContentHandler textHandler = new BodyContentHandler(int writeLimit);
于 2011-05-26T20:37:27.260 回答