2

我遇到了一个问题,我使用 tableview 作为侧边栏来展示应用程序中的某些控制器。当尝试为付款预设 Adyen 结帐时,出现一个错误,告诉我我不能使用多重呈现,我的问题是,我该如何解决这个问题?

我想在按下结帐按钮后关闭侧边栏或按下侧边栏并展示其他控制器,但没有成功或者我做得不对。

谢谢!

这是放在 MainViewController 中的侧边菜单按钮

public func setSideMenuButton()
    {
        let button = UIButton()
        button.frame = CGRect(x: self.view.frame.size.width - 65, y: self.view.frame.size.height - 160, width: 50, height: 50)
        button.setImage(#imageLiteral(resourceName: "side_menu_button").withRenderingMode(.alwaysOriginal), for: .normal)
        button.addTarget(self, action: #selector(buttonAction), for: .touchUpInside)
        self.view.addSubview(button)

    }
    
    @objc func buttonAction(sender: UIButton!)
    {
        pauseEachExistingVideoPlayer()
        
        guard let sideMenuViewController = storyboard?.instantiateViewController(withIdentifier: "SideMenuViewController") as? SideMenuViewController else { return }
      
        sideMenuViewController.modalPresentationStyle = .overCurrentContext
        sideMenuViewController.transitioningDelegate = self
        present(sideMenuViewController, animated: true)
    } 

显示表格中的每个索引

 override func tableView(_ tableView: UITableView, didSelectRowAt indexPath: IndexPath)
    {
    
        switch indexPath.row {
        case 0: present( UIStoryboard(name: "Profile", bundle: nil).instantiateViewController(withIdentifier: "UserProfileVC") as UIViewController, animated: true, completion: nil)
        case 1: present( UIStoryboard(name: "Main", bundle: nil).instantiateViewController(withIdentifier: "SR_VideoLibrary") as UIViewController, animated: true, completion: nil)
        case 2: present( UIStoryboard(name: "Main", bundle: nil).instantiateViewController(withIdentifier: "SR_Livestream") as UIViewController, animated: true, completion: nil)
        case 3: return
        case 4: return
        case 5: present( UIStoryboard(name: "VideoLibrary", bundle: nil).instantiateViewController(withIdentifier: "ProjectsListVC") as UIViewController, animated: true, completion: nil)
        case 6: present( UIStoryboard(name: "Profile", bundle: nil).instantiateViewController(withIdentifier: "GetPremiumVC") as UIViewController, animated: true, completion: nil)
            
        default:
            break
        } 
    }

这就是我在外面点击时关闭约束视图并关闭侧边栏的方式

class SideMenuViewController: UIViewController, UITableViewDelegate
{
    @IBOutlet weak var modalView: UIView!
    
    override func viewDidLoad() {
        super.viewDidLoad()

        if let view = modalView
        {
            addTapGesture(target: view, action: #selector(dismissController))
        }
       
    }
    
    @objc private func dismissController()
    {
        dismiss(animated: true, completion: nil)
    }

}
extension SideMenuViewController {
    func addTapGesture(target: UIView, action: Selector, numberOfTaps: Int = 1) {
        let tap = UITapGestureRecognizer(target: self, action: action)
        tap.numberOfTapsRequired = numberOfTaps
        target.isUserInteractionEnabled = true
        target.addGestureRecognizer(tap)
    }
}

这是侧面菜​​单故事板

4

1 回答 1

2

恐怕这是 UIKit 的一个限制,一个 View Controller 只能呈现另一个 ViewController。

So how I see it, you have two choices, either dismiss the already presented SideMenuViewController first, or make the SideMenuViewController present the Adyen view controller.

If you are using Adyen checkout SDK 3.5.0, there is a helper property added to every instance of a UIViewController that gets the top most presented view controller, use this property of the MainViewController -or any other view controller that would make sense to present the adyen checkout view controller- to present another one on top of it.

presenterViewController.adyen.topPresenter.present(secondPresentedVC, animated: true)

if you're using a version of the SDK in which this adyen helper is not present, you can implement an extension of UIViewController as follows:

extension UIViewController {

    var topPresenter: UIViewController {
        var topController: UIViewController = self
        while let presenter = topController.presentedViewController {
            topController = presenter
        }
        return topController
    }

}

Hope this helps!.

于 2020-04-29T07:44:29.313 回答