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我正在考虑加入一些on()做完全相同的事情的“”，从而节省代码行，这可能吗？

举一个我的代码示例：

const peopleReducer = createReducer(
    INIT_STATE,
    on(fromPeopleAction.GET_ALL_SUCCESS, (state, { peoples }) => adapter.addMany(peoples, { ...state, loading: false })),
    on(fromPeopleAction.GET_ALL_FAIL, (state, { error }) => ({ ...state, error, loading: false })),
    on(fromPeopleAction.CREATE_SUCCESS, (state, { people }) => adapter.addOne(people, { ...state, loading: false })),
    on(fromPeopleAction.CREATE_FAIL, (state, { error }) => ({ ...state, error, loading: false })),
    on(fromPeopleAction.DELETE_SUCCESS, (state, { id }) => adapter.removeOne(id, { ...state, loading: false })),
    on(fromPeopleAction.DELETE_FAIL, (state, { error }) => ({ ...state, error, loading: false }))
);

请注意，我们有一些“ on()”做同样的事情，是否可以为同一个调用多个动作on()？

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1 回答 1

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从on's 的重载来看，我认为如果你这样做，你可以对多个动作使用相同的逻辑：

on(action1, action2, action3, ...action10, (state, action) => {})

请注意，执行 10 次操作后，您将丢失类型。

同样重要的是要注意最后一个参数应该是reducer。

于 2020-04-24T07:12:18.123 回答