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嗨,我试图使用打击代码向https://www.playerup.com/发出请求:

import requests
header = {"user-agent": "Mozilla/5.0 (Windows NT 10.0; Win64; x64) AppleWebKit/537.36 (KHTML, like Gecko) Chrome/80.0.3987.163 Safari/537.36"}
r = requests.get("https://www.playerup.com/",headers=header)
print(r.status_code)

但它给了我一个 [503] 类型错误,我尝试超时 5 秒并且也不起作用我应该如何修复它?

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1 回答 1

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所以有时使用引用和谷歌缓存可以帮助您避免这些故障。所以你的代码应该是:

# here added a referer
header = {"user-agent": "Mozilla/5.0 (Windows NT 10.0; Win64; x64) AppleWebKit/537.36 (KHTML, like Gecko) Chrome/74.0.3729.169 Safari/537.36" ,'referer':'https://www.google.com/'}
# now use a google cache
r = requests.get("http://webcache.googleusercontent.com/search?q=cache:www.playerup.com/",headers=header)

现在查看状态码:

>>>r
<Response [200]>
于 2020-04-22T02:39:56.547 回答