对于相对较浅的“树深度”,您可以使用自联接的 UNION 来匹配子记录与其父母和祖父母的数量。例如,一个名为 [tbl] 的表包含
Key Value Parent Amount GroupName
--- ---------- ------ ------ ---------
1 TopItem1 5 Group1
2 TopItem2 6 Group1
3 Category1 7 Group1
4 Category2 8 Group1
5 Ca1Item1 3 20 Group1
6 Ca1Item2 3 40 Group1
7 Ca2Sub1 4 60 Group1
8 Ca2Sub2 4 80 Group1
9 Ca2Sub1It1 7 400 Group1
10 Ca2Sub1It2 7 500 Group1
11 Ca2Sub2It1 8 600 Group1
查询
SELECT t.Value, t.Amount, t.GroupName FROM tbl t
UNION ALL
SELECT t2.Value, t1.Amount, t1.GroupName
FROM
tbl t1
INNER JOIN
tbl t2
ON t1.Parent = t2.Key
UNION ALL
SELECT t3.Value, t1.Amount, t1.GroupName
FROM
(
tbl t1
INNER JOIN
tbl t2
ON t1.Parent = t2.Key
)
INNER JOIN
tbl t3
ON t2.Parent = t3.Key
会回来
- 每个“价值”本身的金额,
- 每个“值”的子记录的金额,以及
- 每个“值”的孙记录的金额
生产
Value Amount GroupName
---------- ------ ---------
TopItem1 5 Group1
TopItem2 6 Group1
Category1 7 Group1
Category2 8 Group1
Ca1Item1 20 Group1
Ca1Item2 40 Group1
Ca2Sub1 60 Group1
Ca2Sub2 80 Group1
Ca2Sub1It1 400 Group1
Ca2Sub1It2 500 Group1
Ca2Sub2It1 600 Group1
Category1 20 Group1
Category1 40 Group1
Category2 60 Group1
Category2 80 Group1
Ca2Sub1 400 Group1
Ca2Sub1 500 Group1
Ca2Sub2 600 Group1
Category2 400 Group1
Category2 500 Group1
Category2 600 Group1
因此,如果我们将其包装在交叉表查询中
TRANSFORM Sum([Amount]) AS whatever
SELECT [GroupName]
FROM
(
SELECT t.Value, t.Amount, t.GroupName FROM tbl t
UNION ALL
SELECT t2.Value, t1.Amount, t1.GroupName
FROM
tbl t1
INNER JOIN
tbl t2
ON t1.Parent = t2.Key
UNION ALL
SELECT t3.Value, t1.Amount, t1.GroupName
FROM
(
tbl t1
INNER JOIN
tbl t2
ON t1.Parent = t2.Key
)
INNER JOIN
tbl t3
ON t2.Parent = t3.Key
)
GROUP BY [GroupName]
PIVOT [Value]
我们得到
GroupName Ca1Item1 Ca1Item2 Ca2Sub1 Ca2Sub1It1 Ca2Sub1It2 Ca2Sub2 Ca2Sub2It1 Category1 Category2 TopItem1 TopItem2
--------- -------- -------- ------- ---------- ---------- ------- ---------- --------- --------- -------- --------
Group1 20 40 960 400 500 680 600 67 1648 5 6