0

我有两个空间点数据集，一个用于起点，一个用于目的地。

我想从这些坐标中获取最经常出现的轨迹。

> salidas
class       : SpatialPointsDataFrame 
features    : 4385 
extent      : -8.694846, -8.339238, 41.00827, 41.25749  (xmin, xmax, ymin, ymax)
crs         : +init=epsg:4326 +proj=longlat +datum=WGS84 +no_defs +ellps=WGS84 +towgs84=0,0,0 
variables   : 3
names       :               cod, duracion, franja_h 
min values  : 1.37263685362e+18,      315,        1 
max values  : 1.37274729362e+18,    13830,       96 

> llegadas
class       : SpatialPointsDataFrame 
features    : 4385 
extent      : -8.756604, -7.739523, 40.48858, 41.4262  (xmin, xmax, ymin, ymax)
crs         : +init=epsg:4326 +proj=longlat +datum=WGS84 +no_defs +ellps=WGS84 +towgs84=0,0,0 
variables   : 3
names       :               cod, duracion, franja_h 
min values  : 1.37263685362e+18,      315,        1 
max values  : 1.37274729362e+18,    13830,       96

我认为这些点应该保持谨慎，因为它们不是太具体，也不会提供太多信息，所以我为它制作了一个 X 和 Y 坐标网格。

> GridSalidas
          X       Y Count
1   -8.3375 41.1975     1
2   -8.5125 41.2025     1
3   -8.5325 41.1425     1
4   -8.5325 41.2075     1
5   -8.5325 41.2225     1
6   -8.5475 41.2025     1
7   -8.5475 41.2075     1
8   -8.5475 41.2325     1
9   -8.5525 41.2075     1
10  -8.5525 41.2175     1

> GridLlegadas
          X       Y Count
1   -7.7375 41.2975     1
2   -7.8625 40.4875     1
3   -8.1475 41.1875     1
4   -8.3075 41.1975     1
5   -8.4725 41.3225     1
6   -8.4875 41.1875     1
7   -8.4925 41.1925     1
8   -8.4975 41.1875     2
9   -8.5025 41.0425     1
10  -8.5025 41.1925     1

因此，我想根据起点和终点找出哪些轨迹更常见。

谢谢！

4

1 回答 1

1

您所要求的只是一些多维分箱。

dt为了演示，我生成了一个随机的起点和终点数据集。输出结果是一个data.table，它给出了关于最频繁轨迹的以下信息：

  • 定义源网格的 xy 坐标的下限和上限
  • 定义目标网格的 xy 坐标的下限和上限
  • 数数
library(data.table)
library(magrittr)

N <- 5000
set.seed(123)
gp <- 0.1 #grid precision

# Generate an example dataset -----
{
  dt <- data.table(
    origin_x = rnorm(N, 1, 0.1),
    origin_y = rnorm(N, 2, 0.1),
    destination_x = rnorm(N, 11, 0.1),
    destination_y = rnorm(N, 12, 0.1)
  )
}

# Grid formation ----
{
  ## Defining the ranges (LL and UL stand for lower and upper limits, respectively) ----
  {
    origin_x_LL <- dt[, origin_x] %>% min %>% divide_by(gp) %>% floor %>% multiply_by(gp)
    origin_x_UL <- dt[, origin_x] %>% max %>% divide_by(gp) %>% ceiling %>% multiply_by(gp)
    origin_y_LL <- dt[, origin_y] %>% min %>% divide_by(gp) %>% floor %>% multiply_by(gp)
    origin_y_UL <- dt[, origin_y] %>% max %>% divide_by(gp) %>% ceiling %>% multiply_by(gp)
    destination_x_LL <- dt[, destination_x] %>% min %>% divide_by(gp) %>% floor %>% multiply_by(gp)
    destination_x_UL <- dt[, destination_x] %>% max %>% divide_by(gp) %>% ceiling %>% multiply_by(gp)
    destination_y_LL <- dt[, destination_y] %>% min %>% divide_by(gp) %>% floor %>% multiply_by(gp)
    destination_y_UL <- dt[, destination_y] %>% max %>% divide_by(gp) %>% ceiling %>% multiply_by(gp)
  }
  ## Forming the breaks for binning ----
  {
    origin_x_brks <- seq(origin_x_LL, origin_x_UL, by = gp)
    origin_y_brks <- seq(origin_y_LL, origin_y_UL, by = gp)
    destination_x_brks <- seq(destination_x_LL, destination_x_UL, by = gp)
    destination_y_brks <- seq(destination_y_LL, destination_y_UL, by = gp)
  }
  ## Computing the number of bins ----
  {
    origin_x_Nbin <- length(origin_x_brks) - 1L
    origin_y_Nbin <- length(origin_y_brks) - 1L
    destination_x_Nbin <- length(destination_x_brks) - 1L
    destination_y_Nbin <- length(destination_y_brks) - 1L
  }
  ## Binning ----
  {
    origin_x_bin <- .bincode(dt[, origin_x], origin_x_brks, include.lowest = T)
    origin_y_bin <- .bincode(dt[, origin_y], origin_y_brks, include.lowest = T)
    destination_x_bin <- .bincode(dt[, destination_x], destination_x_brks, include.lowest = T)
    destination_y_bin <- .bincode(dt[, destination_y], destination_y_brks, include.lowest = T)
  }
}

# Counting grid frequency ----
{
  grid_count <-
    lapply(seq(origin_x_Nbin), function(i) {
      lapply(seq(origin_y_Nbin), function(j) {
        lapply(seq(destination_x_Nbin), function(m) {
          lapply(seq(destination_y_Nbin), function(n) {
            this_count = which(origin_x_bin == i & origin_y_bin == j & destination_x_bin == m & destination_y_bin == n) %>% length
            return(data.table(origin_x_LL = origin_x_brks[i], origin_x_UL = origin_x_brks[i + 1],
                              origin_y_LL = origin_y_brks[j], origin_y_UL = origin_y_brks[j + 1],
                              destination_x_LL = destination_x_brks[m], destination_x_UL = destination_x_brks[m + 1],
                              destination_y_LL = destination_y_brks[n], destination_y_UL = destination_y_brks[n + 1],
                              count = this_count))
          }) %>% rbindlist
        }) %>% rbindlist
      }) %>% rbindlist
    }) %>% rbindlist
}

# Getting the most frequent grid ----
{
  print(grid_count[count == max(count)])
}
于 2020-04-18T11:37:09.443 回答