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我正在尝试在未收到响应后实施请求重试。我在 Httpclient 教程中阅读了它。HttpRequestRetryHandler 只被调用一次，然后抛出异常。我在这里做错了什么？

更新
我if在 SocketTimeoutException 的异常处理中添加了一个条件。
但是从那里做什么呢？我该如何重试？

private void setRetry(int executionCount)
{
    myRetryHandler = new HttpRequestRetryHandler() {

        public boolean retryRequest(IOException exception,int executionCount,HttpContext context) {

            if (executionCount >= 4) {
                // Do not retry if over max retry count
                System.out.println("retry count");
                return false;
            }
            if (exception instanceof NoHttpResponseException) {
                System.out.println("NoHttpResponseException exception");// Retry if the server dropped connection on us
                return true;
            }
            if (exception instanceof SSLHandshakeException) {
                // Do not retry on SSL handshake exception
                System.out.println("SSLHandshakeException exception");
                return false;
            }
            if (exception instanceof java.net.SocketTimeoutException) {
              // Do not retry on SSL handshake exception
              System.out.println("java.net.SocketTimeoutException exception");
              return false;
            }
            HttpRequest request = (HttpRequest) context.getAttribute( ExecutionContext.HTTP_REQUEST);
            boolean idempotent = !(request instanceof HttpEntityEnclosingRequest); 
            if (idempotent) {
                System.out.println("idempotent exception");
                // Retry if the request is considered idempotent 
                return true;
            }
            return false;
        }
    };
}
public  String postHttpReqest(int retries,
                              int socketTimeoutMillis,
                              int isSSL,
                              String target,
                              String url,
                              String base_url,
                              int port,
                              LinkedHashMap<String, String> lHashMapParams) throws Exception 
{


    HttpParams httpParams = new BasicHttpParams();
    HttpConnectionParams.setConnectionTimeout(httpParams, 50000);
    HttpConnectionParams.setSoTimeout(httpParams, socketTimeoutMillis);         
    defaulthttpclient = new DefaultHttpClient(httpParams);

    setRetry(retries);  // here i set the handler 
    defaulthttpclient.setHttpRequestRetryHandler(myRetryHandler);

    String line = "";

    List<BasicNameValuePair> params = new ArrayList<BasicNameValuePair>();
    for (String key : lHashMapParams.keySet()) {
        String val = lHashMapParams.get(key);
        params.add(new BasicNameValuePair(key,val));

    }

    UrlEncodedFormEntity query = new UrlEncodedFormEntity(params); 
    HttpPost httppost = new HttpPost(url+":"+Integer.toString(port)+"//"+base_url);
    httppost.setEntity(query);
    HttpResponse response_ = defaulthttpclient.execute(httppost);
    HttpEntity entity = response_.getEntity();

    if (entity != null) {
        line = EntityUtils.toString(entity);
        System.out.println(line);

    }

    return line;
}

在服务器中，我设置了断点，因此它将保持连接并且不会返回响应。我在 Httpclient 中遇到的错误：

java.net.SocketTimeoutException: Read timed out
    at java.net.SocketInputStream.socketRead0(Native Method)
    at java.net.SocketInputStream.read(SocketInputStream.java:129)
    at org.apache.http.impl.io.AbstractSessionInputBuffer.fillBuffer(AbstractSessionInputBuffer.java:149)
    at org.apache.http.impl.io.SocketInputBuffer.fillBuffer(SocketInputBuffer.java:110)
    at org.apache.http.impl.io.AbstractSessionInputBuffer.readLine(AbstractSessionInputBuffer.java:260)
    at org.apache.http.impl.conn.LoggingSessionInputBuffer.readLine(LoggingSessionInputBuffer.java:115)
    at org.apache.http.impl.conn.DefaultResponseParser.parseHead(DefaultResponseParser.java:98)
    at org.apache.http.impl.io.AbstractMessageParser.parse(AbstractMessageParser.java:252)
    at org.apache.http.impl.AbstractHttpClientConnection.receiveResponseHeader(AbstractHttpClientConnection.java:281)
    at org.apache.http.impl.conn.DefaultClientConnection.receiveResponseHeader(DefaultClientConnection.java:247)
    at org.apache.http.impl.conn.AbstractClientConnAdapter.receiveResponseHeader(AbstractClientConnAdapter.java:219)
    at org.apache.http.protocol.HttpRequestExecutor.doReceiveResponse(HttpRequestExecutor.java:298)
    at org.apache.http.protocol.HttpRequestExecutor.execute(HttpRequestExecutor.java:125)
    at org.apache.http.impl.client.DefaultRequestDirector.tryExecute(DefaultRequestDirector.java:633)
    at org.apache.http.impl.client.DefaultRequestDirector.execute(DefaultRequestDirector.java:454)
    at org.apache.http.impl.client.AbstractHttpClient.execute(AbstractHttpClient.java:820)
    at org.apache.http.impl.client.AbstractHttpClient.execute(AbstractHttpClient.java:754)
    at org.apache.http.impl.client.AbstractHttpClient.execute(AbstractHttpClient.java:732)
    at com.fts.lb.connector.ut.HttpClientImpl.postHttpReqest(HttpClientImpl.java:183)
4

2 回答 2

3

嗯..您的 RetryHandler 专门为 SocketTimeoutException 返回 false。所以我希望它会在 100% 的时间内抛出异常，事实就是如此。

如果您希望在收到响应之前客户端超时时重试请求，那么您需要让您的 RetyrHandler 为 SocketTimeOutExceptions 返回 true。您可能还想在重试之前增加 SocketTimeOut。

于 2011-07-16T10:18:25.560 回答
1

谷歌了一下，我在 HttpClient 4.1 客户端（仅在 Windows 上）中发现了这个错误。

对于我的问题，我已经使用了最新的 4.1.1，但也许我必须实现 retryHandler。

我希望它会有所帮助。

于 2011-05-27T06:16:30.970 回答