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如何等待我的服务器更新？我正在设置我的HttpServer并且可以从我自己的状态中获得响应，我createContext handle使用我的GET方法传递给 ，但是当我需要等待用户（我）单击 Spotify auth 链接以重定向回我的服务器时 -

java.util.concurrent.ExecutionException: java.io.IOException: HTTP/1.1 header parser received no bytes

如果我手动设置标题字符串，我GET将返回正文。我已经尝试过serverSocket（CompleteableFuture async(request, HttpResponse.BodyHandlers.ofString()来自https://openjdk.java.net/groups/net/httpclient/recipes.html#asynchronousGet）并且仍然得到上述异常。

在 Chrome 中，当我打开http://localhost:8080时，Spotify 代码就在那里。

我想我需要循环client.send(request, HttpResponse.BodyHandleers.ofString()直到服务器状态代码更新，或者设置等待时间？

这是我一直在测试的时间。

public static void startHttpServer() {
        try {

        server = HttpServer.create();
        server.bind(new InetSocketAddress(8080), 0);
        server.createContext("/", new HttpHandler() {
            @Override
            public void handle(HttpExchange exchange) throws IOException {
                String query = /*"hey buddy, this is a Java server, wouldn't you know"; */exchange.getRequestURI().getQuery();
                exchange.sendResponseHeaders(200, query.length());
                exchange.getResponseBody().write(query.getBytes());
                exchange.getResponseBody().close();
            }
        });
        server.start();
        System.out.println("*** Started server ***");
        System.out.println("Use this link to request the access code:");
        System.out.println("https://accounts.spotify.com/authorize?client_id=6edb9b1ac21042abacc6daaf0fbc4c4d&redirect_uri=http://localhost:8080&response_type=code");

    } catch (IOException e) {
        e.printStackTrace();
    }
}

/*public static void getResponse() { // get the response from the server?!
    try {
        HttpClient client = HttpClient.newBuilder().connectTimeout(Duration.ofSeconds(15)).build();
        HttpRequest request = HttpRequest.newBuilder()
                .uri(URI.create("http://localhost:8080"))
                .GET()
                .build();
        HttpResponse<String> response = client.send(request, HttpResponse.BodyHandlers.ofString());
        System.out.println(response.body());
    } catch (IOException | InterruptedException e) {
        e.printStackTrace();
    } finally {
        server.stop(1);
    }
}*/

public static CompletableFuture<String> get() {
    HttpClient client = HttpClient.newHttpClient();
    HttpRequest request = HttpRequest.newBuilder()
            .uri(URI.create("http://localhost:8080"))
            .GET()
            .build();
    return client.sendAsync(request, HttpResponse.BodyHandlers.ofString())
            .thenApply(HttpResponse::body);
}

我正在关注 Hyperskill.org 项目。这就是该阶段完成后代码的行为方式。

> new
Please, provide access for application.
> auth
use this link to request the access code:
https://accounts.spotify.com/authorize?client_id=a19ee7dbfda443b2a8150c9101bfd645&redirect_uri=http://localhost:8080&response_type=code
waiting for code...
code received
making http request for access_token...
response:
{"access_token":"BQBSZ0CA3KR0cf0LxmiNK_E87ZqnkJKDD89VOWAZ9f0QXJcsCiHtl5Om-EVhkIfwt1AZs5WeXgfEF69e4JxL3YX6IIW9zl9WegTmgLkb4xLXWwhryty488CLoL2SM9VIY6HaHgxYxdmRFGWSzrgH3dEqcvPoLpd26D8Y","token_type":"Bearer","expires_in":3600,"refresh_token":"AQCSmdQsvsvpneadsdq1brfKlbEWleTE3nprDwPbZgNSge5dVe_svYBG-RG-_PxIGxVvA7gSnehFJjDRAczLDbbdWPjW1yUq2gtKbbNrCQVAH5ZBtY8wAYskmOIW7zn3IEiBzg","scope":""}
---SUCCESS---
> new
---NEW RELEASES---
Mountains [Sia, Diplo, Labrinth]
Runaway [Lil Peep]
The Greatest Show [Panic! At The Disco]
All Out Life [Slipknot]
> exit
---GOODBYE!---
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1 回答 1

1

我刚刚通过了这个阶段并且遇到了同样的错误，问题是可能导致此错误消息的错误并不像看起来那么具体。对我来说，这是因为来自“exchange.getRequestURI().getQuery()”的空值我在这个潜在的空值上调用 .startsWith("code'") 导致永远不会发送响应，然后是“HTTP/1.1标头解析器未收到任何字节”。您可能期望程序崩溃并在控制台上收到不同的错误消息，但是服务器在与主线程不同的线程中运行，因此服务器线程不是主线程崩溃。

于 2020-09-30T05:44:06.300 回答