0

我期待制作某种电报国际象棋机器人。所以它基于内联键盘。用户应该按下 ilnlineButton 来选择一个棋子，然后按下按钮将棋子放在哪里。我不知道如何在 inlineKeyboard 中的“棋盘”上选择一个空闲单元格，仅在现在选择典当。我试图做 bot.register_next_step_handler 但他没有给出我的预期。

@bot.callback_query_handler(func=lambda call: True)
def callback_inline(call):
    try:
        if call.message:
            if call.data == "suck":
                bot.send_message(call.message.chat.id, "Just wait a bit, OK?")
            elif call.data == "frick":
                bot.send_message(call.message.chat.id, "No, frick you")
            elif call.data == "sad":
                bot.send_message(call.message.chat.id, "Well, shit happens")
            elif call.data == "good":
                bot.send_message(call.message.chat.id, "I am soulless robot. How do      you think I can feel?")
            elif call.data.partition('pawn')[1] == "pawn":
                bot.register_next_step_handler(call.data, process_move_step)

else:
                bot.send_message(call.message.chat.id, call.data)
                bot.edit_message_text(chat_id=call.message.chat.id, message_id=call.message.message_id, text=
                                                                                                      "some_text",reply_markup=None)

    except Exception as e:
        print(repr(e))


def process_move_step(call):
    try:
        if call.message:
            if call.data.partition('empty')[1] == "empty":
                next_move = new_board.get_chessman(call.data)
                new_board.move(call, next_move.X, next_move.Y)
                bot.send_message(call.message.chat.id, "Moved to "+str(next_move.X+str(next_move.Y)))
                print(new_board)

    except Exception as e:
        print(repr(e))

所以我希望进程跳转到 process_move_step 并等待新的回调并在那里检查它，但是在得到“pawn”回调而不是得到“空”回调之后，我从 else: part 而不是进入那个 if

if call.data.partition('empty')[1] == "empty":

So how can I get "pawn" cell then "empty" cell from callbacks and then complete functions. For "empty" stands object EmptyCell and it has attributes X and Y, so I can move pawn in exact place in Board obj and edit inline keyboard. I have seen something similar in @TrueMafiaBot. When police officer is asked if he want to check or shoot somebody and then he picks a player to make chosen action.

4

2 回答 2

1

It doesn't work as you expected. Every request always passes to your main function (callback_inline). So if you try to catch the next step after pawn selection you should save the current status of a user. If the user selects pawn then his status sets is_pawn_selected = true. After this, you can add some logic for processing this status. In your case, it should be something like this:

 if (users.get(user_ID).is_pawn_selected) { 
    user.is_pawn_selected = false
    process_move_step 
}
于 2020-04-11T13:47:58.777 回答
0

The most straightforward way is to hold some state when running a bot and perform if-else checks on callback query answer. For example, you can do something like:

from enum import Enum
from dataclasses import dataclass


class Color(Enum):
    WHITE = 0
    BLACK = 1


@dataclass
class GameState:
    chat_id: int
    turn: Color
    holding_chessman: Chessman
    # ...another useful data for game flow


# data is your callback data received from users
# gamestate is local instanse of GameState on server (or database)

# inside callback answer handling:
if gamestate.turn != data.user.color:
    return error('Not your turn, hold on!')
if gamestate.holding_chessman is None:
    gamestate.holding_chessman = data.pressed_figure
    return info('Now press a button where to move a chessman.')
else:
    perform_chessman_move()
    switch_turn()
    return info('You moved a chessman, now another user must turn')
于 2020-04-12T14:17:45.340 回答