1

我有 2 张桌子

cbmsH

hh_id   | name  | age
9437556 | John  | 40
9886016 | Doe   | 35

建立信任关系

hh_id   | name  | age
9437556 | Peter | 41
9886016 | Tony  | 35
9886016 | Thor  | 32
9886016 | Loki  | 30

我期待这样

hh_id   | name  | age
9437556 | John  | 40
9437556 | Peter | 41
____________________________

hh_id   | name  | age
9886016 | Doe   | 35
9886016 | Tony  | 35
9886016 | Thor  | 32
9886016 | Loki  | 30
____________________________

我试过这个

SELECT cbmsh.hh_id AS head_hhid, cbmsh.barangay AS head_barangay, cbmsh.memno AS head_memno,cbmsh.last_name AS head_last ,cbmsh.first_name AS head_first ,cbmsh.mid_name AS head_mid,cbmsh.relationship,cbmsh.sex AS head_sex,cbmsh.birthdate AS head_birthdate,cbmsh.age AS head_age,cbmsh.occupation AS head_occupation,cbmsh.pwd_ind, cbms.hh_id AS mem_hhid, cbms.barangay, cbms.memno,cbms.last_name AS mem_last,cbms.first_name AS mem_first,cbms.mid_name AS mem_mid,cbms.relationship AS mem_relationship,cbms.sex AS mem_sex,cbms.birthdate AS mem_birthdate,cbms.age AS mem_age,cbms.occupation AS mem_occupation,cbms.pwd_ind
FROM cbmsh, cbms
WHERE cbmsh.hh_id = cbms.hh_id
GROUP BY head_hhid

但它只显示 1 个这样的数据。而不是显示具有相同 hh_id 的所有记录

hh_id   | name  | age
9886016 | Doe   | 35
9886016 | Tony  | 35

有人可以帮我吗？任何帮助将不胜感激！今天是个好日子

4

1 回答 1

0

你有两个问题。

  1. 你不想要JOIN桌子，你想要UNION它们。JOIN用于将两个表的相关行合并为结果中的一行。但是您希望将所有行分开。
  2. 您不想要GROUP BY，它用于将具有相同列值的行聚合到单行中（例如，在对行进行计数或求和时）。如果要将行分开但在一起，请使用ORDER BY.

所以查询应该是

SELECT *
FROM (
    SELECT hh_id, name, age
    FROM cbmsh
    UNION
    SELECT hh_id, name, age
    FROM cbms
) x
ORDER BY hh_id
于 2020-04-09T02:15:59.220 回答