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我正在建立一个用户可以上传帖子的网站。每个用户都有一个个人资料页面，他们可以在其中查看他们喜欢的帖子以及他们创建的帖子。在创建的帖子上方有一个删除按钮。当我删除帖子时，它会被删除，但只能从后端删除。在主页和个人资料页面上（如果我再次进入个人资料页面），帖子仍然存在。如果我刷新页面一切正常，但必须有一种方法可以在不刷新的情况下实现这一点，对吧？

我无法重新渲染组件。如您所见，我对编程很陌生。使用这种删除方法，我需要更新 3 个组件（Home.vue、Posts.vue 和 Profile.vue）。

我的个人资料组件/页面的删除按钮 html：

<v-container class="mt-3" v-else>
  <v-flex xs12>
    <h2 class="font-weight-light">
      Created posts
      <span class="font-weight-regular">({{ userPosts.length }})</span>
    </h2>
  </v-flex>
  <v-layout row wrap>
    <v-flex xs12 sm6 v-for="post in userPosts" :key="post._id">
      <v-card class="mt-3 ml-1 mr-2" hover>
        <v-btn color="info" floating fab small dark @click="loadPost(post)">
          <v-icon>edit</v-icon>
        </v-btn>
        <v-btn
          color="error"
          floating
          fab
          small
          dark
          @click="handleDeleteUserPost(post)"
        >
          <v-icon>delete</v-icon>
        </v-btn>

        <v-img
          height="30vh"
          :src="post.imageUrl"
          @click="goToPost(post._id)"
        ></v-img>
        <v-card-text>{{ post.title }}</v-card-text>
      </v-card>
    </v-flex>
  </v-layout>
</v-container>

下面的生命周期挂钩。它在“方法”下：

    handleDeleteUserPost(post) {
  this.loadPost(post, false);
  const deletePost = window.confirm("Do you want to delete your post?");
  if (deletePost) {
    this.$store.dispatch("deleteUserPost", {
      postId: this.postId,
    });
  }
}

vuex store 组件的删除功能。它在“行动”下：

 deleteUserPost: ({ state, commit }, payload) => {
  apolloClient
    .mutate({
      mutation: DELETE_USER_POST,
      variables: payload,
    })
    .then(({ data }) => {
      const index = state.userPosts.findIndex(
        (post) => post._id === data.deleteUserPost._id
      );
      const userPosts = [
        ...state.userPosts.slice(0, index),
        ...state.userPosts.slice(index + 1),
      ];
      commit("setUserPosts", userPosts);
    })
    .catch((err) => {
      console.error(err);
    });
}

来自“商店”的突变

 mutations: {
setPosts: (state, payload) => {
  state.posts = payload;
},
setSearchResults: (state, payload) => {
  if (payload !== null) {
    state.searchResults = payload;
  }
},
setUser: (state, payload) => {
  state.user = payload;
},
setUserPosts: (state, payload) => {
  state.userPosts = payload;
},
setLoading: (state, payload) => {
  state.loading = payload;
},
setError: (state, payload) => {
  state.error = payload;
},
setAuthError: (state, payload) => {
  state.authError = payload;
},
clearUser: (state) => (state.user = null),
clearError: (state) => (state.error = null),
clearSearchResults: (state) => (state.searchResults = []),

},

4

1 回答 1

2

不确定这是否足以解决，但请尝试替换所有这些：

const userPosts = [
  ...state.userPosts.slice(0, index),
  ...state.userPosts.slice(index + 1),
];
commit("setUserPosts", userPosts);

和

commit("removeUserPost", index)

并创建该突变：

removeUserPost(state, index) {
  state.userPosts.splice(index, 1);  // <-- `splice` not `slice` here
}

如果这还不够，请确保您userPosts在组件中使用，例如：

computed: {
  userPosts() {
    return this.$store.state.userPosts;
  }
}
于 2020-04-08T10:13:00.883 回答