在我的 UI 中，我有一个 textview 来显示列表内容。我为该文本视图启用了自动链接和应用程序选择器对话框。如果将 youtube 链接作为内容（如https://youtu.be/x），从应用选择器对话框中选择 youtube 应用后，youtube 应用会打开并显示错误屏幕（错误代码 400）。我不确定它为什么会发生。我在下面提供了我的代码。
public static void getAppChooserDialog(Context context, String url){
List<Intent> targetedShareIntents = new ArrayList<>();
List<String> sharePackages = new ArrayList<>();
List<ResolveInfo> resInfo = context.getPackageManager().queryIntentActivities(createViewIntent(url),0);
if (!resInfo.isEmpty()) {
for (ResolveInfo info : resInfo) {
Intent targetedShare = createViewIntent(url);
if (!info.activityInfo.packageName.equalsIgnoreCase(context.getPackageName()) &&
!sharePackages.contains(info.activityInfo.packageName)) {
if (targetedShare != null) {
targetedShare.setPackage(info.activityInfo.packageName);
sharePackages.add(info.activityInfo.packageName);
}
targetedShareIntents.add(targetedShare);
}
}
if(!targetedShareIntents.isEmpty()) {
Intent chooserIntent = Intent.createChooser(targetedShareIntents.remove(0),
context.getString(R.string.complete_action_using));
chooserIntent.putExtra(Intent.EXTRA_INITIAL_INTENTS,
targetedShareIntents.toArray(new Parcelable[]{}));
context.startActivity(chooserIntent);
}
}
private Intent createViewIntent(String url){
Intent shareIntent = new Intent(Intent.ACTION_VIEW);
shareIntent.setData(Uri.parse(url));
return shareIntent;
}