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我需要通过 jwe 生成加密数据。ruby 的实现可以正常工作。但是python实现不能正常工作。

红宝石实现

require 'jwe'

key =  OpenSSL::PKey::RSA.new File.read 'public.pem'
payload = {user:"admin"}.to_json
puts JWE.encrypt(payload, key, enc: 'A192GCM')

蟒蛇实现

from jwt import jwk_from_pem
from jwcrypto import jwe,jwk
from jwcrypto.common import json_encode
import json

with open("public.pem", "rb") as f:
    key = jwk.JWK.from_pem(f.read())
key = key.public()
token = jwe.JWE(u'{user:"admin"}', json_encode({"alg":"RSA-OAEP","enc":"A192GCM"}))
token.add_recipient(key)
result = token.serialize()
result = json.loads(result)
print(result["protected"] + "." + result["encrypted_key"])

我已经参考了 jwcrypto 的示例。但是生成的令牌不正确。

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1 回答 1

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固定的。我应该使用紧凑而不是手动附加数据。

from jwt import jwk_from_pem
from jwcrypto import jwe,jwk
from jwcrypto.common import json_encode

with open("public.pem", "rb") as f:
    key = jwk.JWK.from_pem(f.read())
key = key.public()
token = jwe.JWE('{"user":"admin"}', json_encode({"alg":"RSA-OAEP","enc":"A192GCM"}))
token.add_recipient(key)
result = token.serialize(compact=True)
print(result)
于 2020-03-23T08:53:15.330 回答