3

我有一张桌子，例如：

|Date         |Name|
--------------------
|'20-May-2011'|Bob |
|'20-May-2011'|Fred|
|'20-May-2011'|Jim |
|'21-May-2011'|Bob |
|'21-May-2011'|Ed  |
|'22-May-2011'|Bill|

我需要一个查询来返回：

|Date         |Count|Names           |
--------------------------------------
|'20-May-2011'|    3|'Bob, Fred, Jim'|
|'21-May-2011'|    2|'Bob, Ed'       |
|'22-May-2011'|    1|'Bill'          |

换句话说，我想要一个列表和按日期计算的名称。我能想到的最好的是：

SELECT list.[Date], [Count], [Names]
FROM (
    SELECT  [Date], 
            STUFF((
                SELECT ', ' + [Name]
                FROM #table t2
                WHERE t2.[Date] = t.[Date]
                ORDER BY [Name]
                FOR XML PATH('')
            ), 1, 2, '') AS [Names]
    FROM #table t
    GROUP BY [Date]
) [list]
INNER JOIN (
    SELECT  [Date], 
            COUNT(*) AS [Count]
    FROM #table t
    GROUP BY [Date]
) [count]
    ON list.[Date] = count.[Date]
ORDER BY [Count] DESC, list.[Date]

有没有更优雅的查询？

4

2 回答 2

6 
SELECT  [Date], 
        COUNT(*) AS [Count],
        STUFF((
            SELECT ', ' + [Name]
            FROM #table t2
            WHERE t2.[Date] = t.[Date]
            ORDER BY [Name]
            FOR XML PATH('')
        ), 1, 2, '') AS [Names]
FROM #table t
GROUP BY [Date]

如果您认为 Name 列可能包含<>'"&您应该这样做：

SELECT  [Date], 
        COUNT(*) AS [Count],
        STUFF((
            SELECT ', ' + [Name]
            FROM #table t2
            WHERE t2.[Date] = t.[Date]
            ORDER BY [Name]
            FOR XML PATH(''), TYPE
        ).value('.', 'varchar(max)'), 1, 2, '') AS [Names]
FROM #table t
GROUP BY [Date]
于 2011-05-20T20:22:17.737 回答
2

并没有好多少——但也许使用单个 CTE 将 XML-PATH 填充“封装”成一种更美观的方式会起作用吗？

;WITH ConsolidatedData AS
(
SELECT  
    [Date], 
    STUFF((
                SELECT ', ' + [Name]
                FROM #table t2
                WHERE t2.[Date] = t.[Date]
                ORDER BY [Name]
                FOR XML PATH('')
            ), 1, 2, '') AS [Names]
    FROM #table t
)
SELECT
    [Date], Names, COUNT(*)
FROM 
    ConsolidatedData
GROUP BY 
    [Date], Names

不确定您是否会将其视为一个“复合”语句，还是两个.... :-)

一句忠告：尽量不要使用 SQL Server 标识符和保留字（如Dateor Order）作为您自己的列和/或表名......它总是相当混乱......

于 2011-05-20T16:50:46.420 回答