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I am new to flutter and trying to integration below library for using Swagger in flutter project. https://github.com/swagger-api/swagger-codegen/tree/master/samples/client/petstore/dart/swagger

Steps which i did so far :

1) 

added the Path in Pubspec.yaml
     swagger:
        path: /path/swagger-codegen-master/samples/client/petstore/dart/swagger

2) main.dart file :

import 'package:swagger/api.dart';

3) added in Pubspec.yaml for swagger file so my project support SDK 2.0.0

 environment:
      sdk: ">=2.0.0-dev.68.0 <3.0.0"

It is working fine Problem is : I can able to access var api_instance = new PetApi(); Which is swagger api implemented in that. How can i use the url of my swagger api which had complete different API as per my project. For eg on url http://petstore.swagger.io/v2 but on http://student.swagger.io/v2 and have complete different request , header and response parameters ? How can i customise it as per my use.

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1 回答 1

1

以下是我链接 swagger API 文件所遵循的步骤， 1. 使用https://editor.swagger.io
为 dart 生成客户端文件2. 替换文件的使用with并导入所需的库。此 BrowserClient 在我的项目中导致构建错误，因为它包含 Web 依赖项
api_client.dartBrowserClient()IOClient()

  class ApiClient {
      String basePath;
      var client = new BrowserClient();//old one
      var client = new IOClient();//should be changed to this

.
.


3.然后创建客户端类来访问API，如下所示，

/// Singleton class for ApiClient
class Client {
  ApiClient apiClient;
  AuthApi _authApi;

  AuthApi get authApi => _authApi;
  static final Client _client = Client._initClient();

  factory Client() {
    return _client;
  }

  Client._initClient() {
    apiClient = ApiClient(
      basePath: "http://yourproject.apilink",
    );
    _authApi = AuthApi(apiClient);
  }
}


4.那么，

class AuthImpl {
  final Client client;

  AuthImpl(this.client) {}

  Future<User> signIn({
    @required String deviceID,
    @required String deviceType,
    @required String phone,
    @required String password,
  }) async {
    AuthLoginResponse authLoginResponse;
    User user;

    authLoginResponse = await client.authApi
        .authPostLogin(deviceID, deviceType, phone, password);
    user = authLoginResponse.payload;
    return user;
  }}
于 2020-10-23T18:19:27.533 回答