这是一个基本的 cxf 使用问题。我们如何/在哪里可以捕获实际的 HTTP 异常/错误。我有点遵循 Interceptor/MessageObserver 概念，但无法使用它们捕获 HTTP 错误。
我在 log4j 日志文件中看到了这个错误。
Caused by: org.apache.cxf.transport.http.HTTPException: HTTP response
'401: Unauthorized' when communicating with http://10.107.172.79/test/_vti_bin/lists.asmx
at org.apache.cxf.transport.http.HTTPConduit$WrappedOutputStream.handleResponseInternal(HTTPConduit.java:1502)
at org.apache.cxf.transpot.http.HTTPConduit$WrappedOutputStream.handleResponse(HTTPConduit.java:1448)
at org.apache.cxf.transport.http.HTTPConduit$WrappedOutputStream.close(HTTPConduit.java:1356)
at org.apache.cxf.transport.AbstractConduit.close(AbstractConduit.java:56)
at org.apache.cxf.transport.http.HTTPConduit.close(HTTPConduit.java:614)
at org.apache.cxf.interceptor.MessageSenderInterceptor$MessageSenderEndingInterceptor.handleMessage(MessageSenderInterceptor.java:62)
... 9 more
只有带有“无法发送消息”的 javax.xml.ws.WebServiceException。调用服务时抛出消息
try{
GetListCollectionResult result = port.getListCollection();
}catch (javax.xml.ws.WebServiceException excep){
}
这就是我们所说的服务。
提供 NTLM 凭据：
Authenticator.setDefault( extended class of Authenticator);
创建服务。
JaxWsProxyFactoryBean factory = new JaxWsProxyFactoryBean();
factory.setServiceClass(ListsSoap.class);
factory.setAddress(list_url);
ListsSoap port = (ListsSoap) factory.create();
更新导管。
..
Client client = ClientProxy.getClient(port);
HTTPConduit http = (HTTPConduit) client.getConduit();
HTTPClientPolicy httpClientPolicy = new HTTPClientPolicy();
httpClientPolicy.setConnectionTimeout(36000);
httpClientPolicy.setAllowChunking(false);
http.setClient(httpClientPolicy);
致电服务并获得结果。
GetListCollectionResult result = port.getListCollection();