1

我有一个Trip模型并创建了一个表格,以便更新现有的旅行。

models.py

class Trip(models.Model):
    trip_id = models.CharField(max_length=20, verbose_name="Ref. Viagem")
    destination = models.CharField(max_length=200, null=True, verbose_name='Destino')
    client = models.ForeignKey(Clients, null=True, on_delete=models.CASCADE, verbose_name="Cliente")
    out_flight = models.ForeignKey(Flight, related_name="outbound_flight" ,null=True, on_delete=models.SET_NULL, verbose_name="Voo Ida")
    hotel = models.ForeignKey(Hotels, null=True, on_delete=models.SET_NULL, verbose_name="Hotel")
    in_flight = models.ForeignKey (Flight, related_name="inbound_flight", null=True, on_delete=models.SET_NULL, verbose_name="Voo Regresso")

forms.py

class UpdateTrip(ModelForm):

    def __init__(self, *args, **kwargs):
        super(UpdateTrip, self).__init__(*args, **kwargs)
        self.fields['trip_id'].widget = TextInput(attrs={'class': 'form-control'})
        self.fields['destination'].widget = TextInput(attrs={'class': 'form-control'})
        self.fields['client'].queryset = Clients.objects.all()


    class Meta:
        model = Trip
        fields = ('trip_id', 'destination', 'client', 'out_flight', 'hotel', 'in_flight')

这就是views.py它的目的:

def trip_upd(request, trip_id):
    if request.method == 'POST':
        form = UpdateTrip(request.POST)
        if form.is_valid():
            form.save()
            return redirect('trips')
    else:
        form = UpdateTrip()
    return render(request, 'backend/trip_update.html', {'form': form})

我在测试时使用准系统形式:

<form method="post">
    {% csrf_token %}
    {{ form }}
    <input type="submit" value="Submit">
</form>

现在,这不会更新对象,而是创建一个新对象。

4

1 回答 1

0

您需要通过参数传递您要更新的实例instance=…

def trip_upd(request, trip_id):
    if request.method == 'POST':
        trip = Trip.objects.get(trip_id=trip_id)
        form = UpdateTrip(request.POST, instance=trip)
        if form.is_valid():
            form.save()
            return redirect('trips')
    else:
        form = UpdateTrip()
    return render(request, 'backend/trip_update.html', {'form': form})

或者您可以使用get_object_or_404函数 [Django-doc]返回 HTTP 404 错误,以防对象不存在:

from django.shortcuts import get_object_or_404

def trip_upd(request, trip_id):
    if request.method == 'POST':
        trip = get_object_or_404(Trip, trip_id=trip_id)
        form = UpdateTrip(request.POST, instance=trip)
        if form.is_valid():
            form.save()
            return redirect('trips')
    else:
        form = UpdateTrip()
    return render(request, 'backend/trip_update.html', {'form': form})

请注意,在表单中,您可以在 中指定小部件Meta,这比在 中编写更具声明性__init__

class UpdateTrip(ModelForm):

    class Meta:
        model = Trip
        fields = ('trip_id', 'destination', 'client', 'out_flight', 'hotel', 'in_flight')
        widgets = {
            'trip_id': TextInput(attrs={'class': 'form-control'}),
            'destination': TextInput(attrs={'class': 'form-control'})
        }
于 2020-03-08T17:08:40.707 回答